Question

Factor the expression over the complex numbers. x^2+18

Answer 1

$x^2+18=\\\\x^2-(-18)=\\\\(x-\sqrt{-18})(x+\sqrt{-18})=\\\\(x-3\sqrt2i)(x+3\sqrt2i)$

Answer 2

Answer:

The factors are $(x-3\sqrt2 i)(x+3\sqrt2 i)$

Step-by-step explanation:

Given : Expression $x^2+18$

To find : Factor the expression over the complex numbers ?

Solution :

Expression $x^2+18$

First we solve for x,

$x^2+18=0$

$x^2=-18$

Taking root both side,

$x=\sqrt{-18}$

$x=\pm 3\sqrt{2}i$

So, The factors are $(x-3\sqrt2 i)(x+3\sqrt2 i)$