See picture hope it helps
Answer:
6c^2-cd-d^2
Step-by-step explanation:
How you get the answer is you use the process called FOIL. The F is front, so you multiply the 2c and the 3c to get 6c^2. The O is the outer, so you multiply the 2c and the d(because they are on the outer sides of the parenthesis) to get 2cd. The I is the inner, so you multiply the -d and the 3c(because they are on the inner sides of the parenthesis) to get -3cd. The L is the last, so you multiply d and -d to get -d^2. The 2cd and the -3cd are the same so you have to minus them to get -cd. So the answer is:
6c^2-cd-d^2.
There you go. I assumed you know how to derrivate!
Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
Answer: I believe the answer is minimum
