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3 years ago

3. The yearly profits of a company is $5,000. The profits have been decreasing by 6% per year.

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

Answer:

5000 X (0.96)^n

$3607

Step-by-step explanation:

Profit decreases at a rate of 6% per year = 100 - 6 = 96%

In year 1, profit would be = 5000 x 0.96 = 4800

In year 2 = 5000 x 0.96^2 =

5000 X (0.96)^n

5000 X (0.96)^8 = $3607

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Evaluate 3 to the power of 3+1⋅9+12<br><br> A.24<br> B.30<br> C.48<br> D.264

Crank

24..... hope I helped

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3 years ago

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For this set of data,<br> 89, 88, 84, 87, 89, 84, 84, 83, 85, 89, 84<br> Find the standard deviation

Ilia_Sergeevich [38]

Answer: 2.2962419891482

Step-by-step explanation: First get the mean of the numbers or the average

the mean in this case is 86

then subtract each number by the mean of 86

the numbers then become : 3, 2, -2, 1, 3, -2, -2, -3, -1, 3, -2

then square all the numbers to get : 9, 4, 4, 1, 9, 4, -4, 9, 1, 9, 4

then find the mean of those numbers which is 5.2727272727273

then find the square root of this number to find the standard deviation

2.2962419891482 is the standard deviation

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6 0

3 years ago

g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od

cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

6 0

3 years ago

Calcular la edades actuales de una madre y sus dos hijos sabiendo que hace 14 años la dad de la madre era 5

rodikova [14]

The present age of mother and her daughter respectively are; 40 and 10 years respectively.

<h3>How to Solve Algebra Word Problems?</h3>

Let x and y be the present age of mother and her daughter respectively.

Therefore;

x + y = 50

x = 50 − y .....(1)

After 20 years, mother's age will be twice her daughter's age at the time. Thus;

x + 20 = 2(y + 20)

x − 2y = 20 .....(2)

Plugging eq 1 into eq 2 gives us;

50 − y − 2y = 20

3y = 30

y = 10

Thus;

x = 50 − 10

x = 40

Thus, the present age of mother and her daughter is 40 and 10 years respectively.

Translation of the question into English is;

The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.

Read more about Algebra Word Problems at; brainly.com/question/21405634

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1 year ago

Please let me know ASAP

aksik [14]

Answer:

∠ BAC = 80°

Step-by-step explanation:

The sum of the interior angles of quadrilateral ACDB = 360°

DB and DC are tangents to the circle, thus

∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )

Thus

∠ BAC + 90° + 90° + 100° = 360°

∠ BAC + 280° = 360° ( subtract 280° from both sides )

∠ BAC = 80°

4 0

3 years ago

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