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2 years ago

What s the factor of (x+3)(x+2)

2 answers:

8 0

Simplifying (x + 3)(x + 2)

Reorder the terms: (3 + x)(x + 2)

Reorder the terms: (3 + x)(2 + x)

Multiply (3 + x) * (2 + x) (3(2 + x) + x(2 + x)) ((2 * 3 + x * 3) + x(2 + x)) ((6 + 3x) + x(2 + x)) (6 + 3x + (2 * x + x * x)) (6 + 3x + (2x + x2))

Combine like terms: 3x + 2x = 5x (6 + 5x + x2)

Factor a trinomial. (3 + x)(2 + x)

Final result:
(3 + x)(2 + x)

SashulF [63]2 years ago

8 0

Basically, don't listen to the other guy, he is making up random stuff, report him.
You can solve this just by multiplying by FOIL
Firsts
Outsides
Insides
Lasts
The firsts of (x+3)(x+2) are x and x, so x*x = x^2
The outsides of (x+3)(x+2) are x and 2, so x*2 = 2x
The insides of (x+3)(x+2) are 3 and x, so 3*x = 3x
The lasts of (x+3)(x+2) are 3 and 2, so 3*2 = 6

Add of of that together, x^2 + 2x + 3x + 6
So the answer is: x^2 + 5x + 6

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Find the missing value for the parallelogram

jeka57 [31]

Answer:

y = 85°

z = 35°

x = 60°

Step-by-step explanation:

y) 180 - 120 = 60, therefore:

180 - (35 + 60)

=> y = 85

=> z = 35

180 - (35 + 85)

=> x = 60

Hope this helps!

3 0

2 years ago

Read 2 more answers

Help me with math questions urgent Thanks

aleksandrvk [35]

Answer: x = 2.65, y = 3.81

Step-by-step explanation:

ABC similar to PQR

1) Find the ratio of corresponding sides

2) Use that ratio to find values for x & y

1) Side AB = 2.76cm & Side PR = y cm

Side BC = x cm & Side RQ = 3.66 cm

Side CA = 3 cm & Side QP = 4.14 cm (both lengths given)

Can match 3 to 4.14 & ratio of sides in ABC to PQR= 3 /4.14

Length of sides ABC = 3/4.14 times the length of sides PQR

2) x = (3 / 4.14) * 3.66 = 2.65

Now solve for y, ABC to PQR: 2.76 = (3 / 4.14) (y )

equality property (both sides) & inverse operation to isolate y : . 2.76 ÷ (3 / 4.14) = (3 / 4.14 ) ÷ (3 / 4.14) (y)

2.76 * (4.14 / 3) = 3 / 4.14 * (4.14 / 3) (y)

(2.76 * 1.38 ) = 3.81 = y

Scale Factor Method: Determine the Multiplier

Small to Big or Big to Small ➜ Be sure not to switch

7 0

2 years ago

Can you help me with this!!!!!!!!!

alexira [117]

a. The first variable is x and the second variable is y.

b. The equations are $x+y=12$ and $x-y=8.$

Step-by-step explanation:

Step 1:

The first step is to define the variables. The variables can be any two symbols, letters, characters, etc.

Here let the first variable be x and the let the second variable be y.

So the variables are defined as x and y.

Step 2:

The sum of the given variables is 12.

The first variable + the second variable = 12,

$x+y=12.$

The difference between the two variables is 4.

The first variable - the second variable = 4.

$x-y=4.$

Step 3:

If we add both the equations we get, $2x =16, x= 8$ and $y=4.$

x = 8 and y = 4.

4 0

2 years ago

2. attached below even though I answered I was guessing this question so I need to know the correct answer

zavuch27 [327]

Volume is defined as area of the base*the hight.

In this question the base is the traingles.

Area of a triangle is base*hight/2, so it 8*6/2= 24

Volume is 24*8(hight)=192

So the answer is 192cm^3

5 0

2 years ago

The rate of change of revenue (in dollars per calculator) from the sale of x calculators is R′(x)=(x+1)ln(x+1)R ′ (x)=(x+1)ln(x+

jekas [21]

Answer:

Total revenue = $\frac{169}{2}\ln(13)-\frac{169}{4}$ dollars

Step-by-step explanation:

$R'(x)=(x+1)\ln(x+1)$

Integrate with respect to $x$ .

$R(x)=$ ∫ $(x+1)\ln(x+1)$ dx

Take $x+1=u$

Differentiate with respect to $x$

$dx=du$

So,

$R(x)=$ ∫ $u\ln(u)\,du$

Use integration by parts: ∫f g dx = f∫ g dx-∫(∫g dx)f' dx

Therefore,

$R(x)=$ $\frac{u^2}{2}\ln(u)$ $-$ ∫ $\frac{u^2}{2}\frac{1}{u}\,du$

= $\frac{u^2}{2}\ln(u)$ $-$ ∫ $\frac{u}{2}\,du$

Put $u=x+1$

$R(x)= \frac{(x+1)^2}{2}\ln(x+1)-\frac{(x+1)^2}{4}$

To find total revenue from the sale of the first 12 calculators, put $x=12$

$R(x)= \frac{(12+1)^2}{2}\ln(12+1)-\frac{(12+1)^2}{4}\\\\= \frac{(13)^2}{2}\ln(13)-\frac{(13)^2}{4}\\\\=\frac{169}{2}\ln(13)-\frac{169}{4}$

Total revenue = $\frac{169}{2}\ln(13)-\frac{169}{4}$ dollars

4 0

2 years ago