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GenaCL600 [577]
3 years ago
13

Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu

e of her car was $25,000 due to depreciation. She is told that the value of her car depreciates linearly.
Find a function V(t) which gives the value of the car t years after the year 2015.
In 2018, Anna is told that she will be given $15,000 for her car if she decides to trade it in for a new car. Use the function from part (1) above to determine the value of her car in 2018.
Is the $15,000 value fair based on what she was told about linear depreciation? Explain your answer?
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

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Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

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3 years ago
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y=9x-5

Step-by-step explanation:

You want to find the equation for a line that passes through the point (1,4) and has a slope of 9.

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y = mx+b

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b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 9. So you can right away fill in the equation for a line somewhat to read:

y=9x+b.

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To find b, think about what your (x,y) point means:

(1,4). When x of the line is 1, y of the line must be 4.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: b is what we want, the 9 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specifically passes through the point (1,4).

So, why not plug in for x the number 1 and y the number 4? This will allow us to solve for b for the particular line that passes through the point you gave!.

(1,4). y=mx+b or 4=9 × 1+b, or solving for b: b=4-(9)(1). b=-5.The equation of the line that passes through the point (1,4) with a slope of 9

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y=9x-5

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bazaltina [42]

Answer: 2


Step-by-step explanation:


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3 years ago
Can a prime number be multiple of any other number except itself?
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3 years ago
Scott and Ariel want to make as much as snack mix as possible, but no more than 25 cups of mix. I they can use only full cups of
photoshop1234 [79]

Answer:

hello your question has some missing parts attached below is the missing information

answer : Scott will make 5 snack mix without going over

Step-by-step explanation:

Given that:

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=  5cups per snacks mix

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