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Sergio039 [100]
2 years ago
10

Questions 15 Poge 1 of 1 Tyrone thinks his turtle walks pretty fast compared to other turtles. He wanted to figure out how fast

it walks. The bar diagram shows how far the turtle walks on land over time. 10.5 in. 1 sec 1 sec 1 sec 3.5 in. 3.5 in. ? Question 1 (1 point) Use the bar diagram to determine how many inches the turtle travels in the third second. The turtle travels inches in the thir
d second. Blank 1:​
Mathematics
2 answers:
lys-0071 [83]2 years ago
6 0

Answer:

3.5 inch Probably is the answer

Step-by-step explanation:

Softa [21]2 years ago
5 0

Answer:

its like 6 chessticks in the back

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Tyler asks for a fish tank for his birthday. The task he wants is a rectangular prism 20 inches long, 10 inches wide, and 12 inc
Natasha_Volkova [10]

Answer:

2400 in^3

Step-by-step explanation:

Tyler asks for a fish tank for his birthday. The task he wants is a rectangular prism 20 inches long, 10 inches wide, and 12 inches tall. How much water will the fish tank hold?

the capacity of the tank can be determined by calculating the volume of the tank

volume of a prism = length x width x height

20 x 10 x 12 = 2400 in^3

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2 years ago
The diagram shows triangle ABC. Calculate the length of AC
igor_vitrenko [27]

Answer:

give full question. where is diagram.

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It costs $x for a round-trip bus ticket to the mall. You have $24. Select an inequality that represents how much money you can s
lorasvet [3.4K]

Answer:you have to make the inequality first

Step-by-step explanation:

4 0
3 years ago
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Rounded 7,499,846 rounded to the nearest 10,000
Genrish500 [490]

Answer:

7,410,000

Step-by-step explanation:

5 0
2 years ago
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Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
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