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Andrei [34K]
4 years ago
15

PLS HELPPPP!!!! Thanks

Mathematics
1 answer:
pishuonlain [190]4 years ago
3 0
The first one I believe
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A) Two non-vertical lines have the same slope if and only if they are parallel.
kenny6666 [7]

Answer: D) If two parallel lines are cut by a transversal, then each pair of alternate interior angles is congruent.

Step-by-step explanation:

Since, By the Alternative interior angle theorem,

When two parallel lines are cut by the same transversal then the alternative interior angles made by the transversal on these parallel lines are congruent to each other.

Here AC ║ A'C'

⇒ AD ║ A'C'

⇒ parallel lines AD and A'C are cut by the same transversal A'D

⇒ ∠ CDB' ≅ ∠ BA'C' -------(1)

Similarly, When, AB ║ A'B

⇒ AB ║ A'D and AB ║EB'

⇒ Parallel lines AB and A'D are cut by the same transversal AD and Parallel lines AB and EB' are cu by the same transversal EB.

⇒ ∠ BAC ≅ ∠CDB' ------(2)   and  ∠ABC ≅ ∠BEB' -------(3)

Also, BC ║ B'C'

⇒ BE ║ B'C'

And, these paralle lines are cut by the same transversal B'E,

Thus, ∠BEB' ≅ ∠ A'B'C' ---------(4)

Thus, By equations (1) and (2),

∠ BAC ≅ ∠B'A'C ( By transitive property of equality )

And, By equation (3) and (4),

∠ABC ≅ ∠ A'B'C' ( By transitive property of equality )

5 0
3 years ago
Todd says (1,4) is a solution to y=2x +2.<br><br> Is he correct?
Alexxandr [17]
Yes, Todd is correct.

y= 2x+2

(1,4)

1=x, 4=y

Plug the numbers in:

4= 2(1)+2

4= 2+2

4=4
4 0
3 years ago
Read 2 more answers
PLZ HELP REALLY NEED ANSWER
frozen [14]

Answer:The formula looks like this: SA=2lw+2lh+2hw, where SA = surface area, l = length, w = width, and h = height. In the rectangular prism net above, l = 8 inches, w = 5 inches, and h = 3 inches.

Step-by-step explanation:

4 0
3 years ago
Graph the linear equation using the slope and​ y-intercept.<br> Y=4X+3
JulsSmile [24]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have y = 4x + 3

m = 4 - slope

3 - y-intercept


m=\dfrac{\Delta Y}{\Delta x}\to4=\dfrac{4}{1}

4 units up and 1 unit right

7 0
3 years ago
What’s the answer help please I need to pass this class
almond37 [142]

c.\ f(x)=\dfrac{18}{x}-9\ \text{and}\ g(x)=\dfrac{18}{x+9}\\\\\text{in f(x), solve for x}\\\\\dfrac{18}{x}-9=y\ \ \ \ |+9\\\\\dfrac{18}{x}=y+9\\\\\dfrac{18}{x}=\dfrac{y+9}{1}\ \ \ \ |\text{cross multiply}\\\\x(y+9)=18\ \ \ \ |:(y+9)\\\\x=\dfrac{18}{y+9}\to f^{-1}(x)=\dfrac{18}{x+9}

5 0
3 years ago
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