Answer:
v=−5
Step-by-step explanation:
2v + 18 = 16 - 4(v + 7)
2v+18=16−4(v+7)
2v+18=16+(−4)(v)+(−4)(7)(Distribute)
2v+18=16+−4v+−28
2v+18=(−4v)+(16+−28)(Combine Like Terms)
2v+18=−4v+−12
2v+18=−4v−12
Add 4v to both sides.
2v+18+4v=−4v−12+4v
6v+18=−12
Subtract 18 from both sides.
6v+18−18=−12−18
6v=−30
Divide both sides by 6.
6v
/6
=
−30
/6
v=−5
- An isosceles triangle ABC
- AD is a bisector of ∠A
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- By ASA criteria ∆ABD congurant to ∆ADC
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- By CPCT ( corresponding parts of congurant triangle )
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Answer:
3 3/8
Step-by-step explanation:
Correct me if I'm wrong
Answer:
x=−2 and y=−1
Step-by-step explanation:
<u>Problem:</u>
Solve y=x2;y=−x−3
<u>Steps:</u>
I will solve your system by substitution.
y=1/2x;y=−x−3
Step: Solve y= 1/2x for y:
Step: Substitute 1/2 x for y in y=−x−3:
y=−x−3
1/2x= =−x−3
1/2x+x=−x−3+x(Add x to both sides)
3/2x = -3
3/2x/3/2 = -3/3/2 (Divide both sides by 3/2)
x=−2
Step: Substitute −2 for x in y=1/2x:
y=1/2x
y=1/2(-2)
y=−1(Simplify both sides of the equation)
<u>Answer:</u>
x=−2 and y=−1
If each of the branches has half the area of the aorta, its linear scale factor is the square root of 1/2, or (√2)/2.
The diameter of one of the branches is (da×√2)/2.
