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Natalija [7]
2 years ago
7

Rewrite y= -2x + 35 in vertex form ?

Mathematics
1 answer:
Lesechka [4]2 years ago
8 0
Are there any multiple choice answers to this?
 
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Write the quadratic equation 3x ^ 2 - 9x = 5 standard form ax²+bx+c=0? in the
sleet_krkn [62]
The answer to your question is B 3x^2-9x-5=0.
8 0
2 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
Naddika [18.5K]

Answer:

First option is the correct answer.

14.29\: m^2

Step-by-step explanation:

Area of circular pond

= \pi {r}^{2}  \\  \\  = 3.14 {(7)}^{2}  \\  \\   = 153.86 \:  {ft}^{2}\\\\=\frac{153.86}{(3.2808)^2}\:m^2\\\\=14.29\: m^2

5 0
2 years ago
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I need to k ow how to do this
Ainat [17]
You just need to trace it without moving your pencil off the paper
3 0
3 years ago
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What is 9.187 to the nearest tenth? And hundredth and one
Assoli18 [71]
<span> 9.187 to the nearest tenth is 9.2

The 1 in 9.187 is in the tenths place and since the number after it is over 5, you round up. </span>
4 0
3 years ago
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How to solve (2.31*10^-6)+(5.87*10^-4)
S_A_V [24]

We want to calculate the following

2.31\cdot10^{-6}+5.87\cdot10^{-4}

Using the properties of exponents, we have that

10^{-6}=10^{-4}\cdot10^{-2}

So we have

2.31\cdot10^{-6}+5.87\cdot10^{-4}=2.31\cdot10^{-2}\cdot10^{-4}+5.87\cdot10^{-4}

So, if factor 10^-4 on the right side, we have

10^{-4}(2.31\cdot10^{-2}+5.87)

Note that

2.31\cdot10^{-2}=0.0231

Then,

5.87+2.31\cdot10^{-2}=5.87+0.0231=5.8931^{}

So we have that

2.31\cdot10^{-6}+5.87\cdot10^{-4}=5.8931\cdot10^{-4}

5 0
1 year ago
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