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Kaylis [27]
2 years ago
10

For the following right triangle, find the side length x. Round your answer to the nearest hundredth

Mathematics
1 answer:
garik1379 [7]2 years ago
3 0

Answer:

7.94

Step-by-step explanation:

a^{2} + 9^{2} =12^{2} \\a^{2} +81 = 144\\a^{2}  = 63\\a = \sqrt{63} \\a= 7.93725

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Naddika [18.5K]
The answer is the first one
7 0
3 years ago
Cuanto vale d+2c-(3a-2b) si a=2,b=-3,c=1,d=-2
kherson [118]
<h3>Solution:</h3>

given \:  \: a=2,b=-3,c=1,d=-2 \\ then \:  \: d + 2c - (3a - 2b) \\  = ( - 2) + 2(1) - (3 \times 2 - 2 \times  -3) \\  =  - 2 + 2 - (6 + 6) \\  = 0 - 12 \\  =  - 12

<h3>Answer:</h3>

-12

<h3>Hope it helps..</h3>

ray4918 here to help..

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3 0
3 years ago
X^2-x-12 factor completely
steposvetlana [31]
Use the sum-product pattern

2
−

−
1
2
x
2
−
x
−
12
x2−x−12

2
+
3

−
4

−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
2
Common factor from the two pairs

2
+
3

−
4

−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12

(

+
3
)
−
4
(

+
3
)
x
(
x
+
3
)
−
4
(
x
+
3
)
x(x+3)−4(x+3)
3
Rewrite in factored form

(

+
3
)
−
4(+3)x
(x+3)−4(x+3)
x(x+3)−4(x+3)
(−4)(+3)
(x−4)(x+3)
(x−4)(x+3)
5 0
2 years ago
The question is in the screenshot
Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

8 0
3 years ago
Response will be saved automatically.
Charra [1.4K]

Answer:

443.28

Step-by-step explanation:

Subtract 42.24 from 570.3 three times.

3 0
3 years ago
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