Answer:
Yes
Step-by-step explanation:
3 x - 2 y = 10
( - 2 , - 8 )
We know that coordinates are put in the form ( x , y ) and from that we can work out that x = -2 and y = -8
Now we just substitute x = -2 and y = -8 into 3 x - 2 y = 10
3 x - 2 y = 10
{ 3 × ( - 2 ) } - { 2 × ( - 8 ) } = 10
{ - 6 } - { - 16 } = 10
- 6 + 16 = 10 True
Answer: Nope.
Step-by-step explanation: All circles are round and have no corners. Therefore, they cannot have any angles - right angles included.
Answer:
Let the matrix associated to the system and
the vector of constant values of the system.
The equation of the line joining p and q is
. Since p and q are solutions of the linear system then, and
Let . Observe that . Then w is a solution of the homogeneous system Ax=0.
Now, let s=p+r(q-p) for some be a point in the line joining p and q. Observe that
Then As=b. This means that s is a solution of the linear system.
The triangles are not similar
The answer is 5. Work backwards: first add 7 to 9, then divide by 2, then subtract 3.
9+7=16
16/2=8
8-3=5
Cross Check:
5+3=8
8*2=16
16-7=9
Final Answer: 5