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Alexxandr [17]
3 years ago
13

What is one half divided by 8

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

Answer:

1/16

Step-by-step explanation:


masha68 [24]3 years ago
4 0

\frac{1}{2}  \div 8 = x
After LCF(Leave,change,flip) it would be
\frac{1}{2}    \times  \frac{1}{8}  = x

Then you would do top times top and bottom times bottom and get
x = \frac{1}{16}
And if you want decimal then you can do
1 \div 16 = x
x =0.0625
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A pizza had 9/10 left before Lucas ate 4/5 of the pizza. How much pizza is left over?
Allushta [10]

Step-by-step explanation:

always try to bring fractions you need to compare to the same denominator (bottom number).

we have 9/10 of the pizza left.

then 4/5 if the pizza are eaten.

how to compare 9/10 with 4/5 ?

by bringing 4/5 also to a fraction of 10ths.

what do I need to multiply 5 with to get 10 ?

right, 2.

since we don't want to change the overall value of the original fraction, we need to multiply both levels (numerator and denominator) by that same factor :

4/5 × 2/2 = 8/10

aha !

that we can compare with 9/10.

so, when Lucas ate 4/5 (= 8/10) of the pizza, when there was originally 9/10 left, then we have 1/10 of the pizza left.

5 0
3 years ago
6.
Drupady [299]
I believe it’s C. 3/2
5 0
3 years ago
F(x) = 73 +11 - 8<br> g(x) = -2<br> Find (f - 3)(x).
laiz [17]

Answer:

The answer is D

Step-by-step explanation:

when \: fx =  |7x + 1|  - 8 \\ while \: y \\ gx =  - 2 \\ therefore \: find(fx - gx) \\  (|7x - 1|  - 8) - ( - 2) \\  |7x - 1|  - 8 + 2 \\   |7x - 1|  - 6

5 0
2 years ago
Read 2 more answers
Let c be the curve which is the union of two line segments, the first going from (0, 0) to (4, 4) and the second going from (4,
victus00 [196]
First of all we need to find a representation of C, so this is shown in the figure below.

So the integral we need to compute is this:

I=\int_c 4dy-4dx

So, as shown in the figure, C = C1 + C2, so:

I=\int_{c_{1}} (4dy-4dx)+\int_{c_{2}} (4dy-4dx)=I_{1}+I_{2}

Computing first integral:

c_{1}: y-y_{0}=m(x-x_{0}) \rightarrow y=x

Applying derivative:

dy=dx

Substituting this value into I_{1}

I_{1}=\int_{c_{1}} (4dx-4dx)=\int_{c_{1}} 0 \rightarrow \boxed{I_{1}=0}

Computing second integral:

c_{2}: y-y_{0}=m(x-x_{0}) \rightarrow y-0=-(x-8) \rightarrow y=-x+8

Applying derivative:

dy=-dx

Substituting this differential into I_{2}

I_{2}=\int_{c_{2}} 4(-dx)-4dx=\int_{c_{2}} -8dx=-8\int_{c_{2}}dx

We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:

 I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}

Finally:

I=\int_c 4dy-4dx=0-32 \rightarrow \boxed{I=-32}
4 0
3 years ago
HELP ME PLEASE ILL GIVE BRAINLIEST
Alex73 [517]

Answer:

la respuesta correcta es la c

step explanation:

la respuesta correcta es la c

7 0
3 years ago
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