We know that for all B:
![\csc\text{B}\in(-\infty,-1]\cup[1,\infty)](https://tex.z-dn.net/?f=%5Ccsc%5Ctext%7BB%7D%5Cin%28-%5Cinfty%2C-1%5D%5Ccup%5B1%2C%5Cinfty%29)
So the answer is 0,5 (b.)
If simplifying it it would be
1/2
Answer:The dragon fly can fly 35/12 miles
Step-by-step explanation:
Speed =distance / time
If the distance A dragonfly flies 7/8 of a mile
And
Time =3/10 of an hour.
Speed =7/ 8 ÷3/10 =7/ 8 x 10/3 =70/24 reducing to lowest term becomes 35/12 miles / hour
Now when the dragon fly flies in 1 hour, its distance covered becomes
Speed =distance / time
35/12 miles / hour=distance / 1
distance =35/12 miles
Answer:
<h3>HERE IS YOUR ANSWER FRIEND, </h3>
∠A + ∠B + ∠C = 180° (angle sum property)
(4x - 13)° + (15)° + (2x + 18)° = 180°
( 4x - 13 + 15 + 2x + 18 )° = 180°
( 6x + 20)° = 180°
6x = 180 - 20
6x = 160
x = 160/6
x = 80/3° (or 26.6666666667 )
we have value of x = 80/3°
°.°∠A = ( 4x - 13 ) = 281/3
°.°∠C = ( 2x + 18 ) = 178/3
Step-by-step explanation:
<h2>HOPE IT HELPED YOU,</h2><h2>
MARK ME AS <em><u>BRAINLIST</u></em><em><u> </u></em></h2>
You can start by making a table that will permit you visualize the model. Start with 28,000 and subtract 700 hundreed step by step, in this way: 1) 28,000 - 700; 2) 28,000 - 2(700); 3) 28,000 - 3(700) ... then you can observe that after t hours the remaining number of gallos in the pool is 28,000 - 700t. So, the equation that models this situation is g(t) = 28,000 - 700t.
