Answer:
i think it was about 5000.
Step-by-step explanation:
I need a photo to tell you the answer
Answer:
102
Step-by-step explanation:
140-38=102
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
Answer:
1). g(-9) = -81.914
2). Last option
Step-by-step explanation:
1). f(x) = x²
For x = -9
f(-9) = (-9)² = 81
g(x) = 
g(-9) = ![\frac{32}{[2(-9)-17]}](https://tex.z-dn.net/?f=%5Cfrac%7B32%7D%7B%5B2%28-9%29-17%5D%7D)
= 
= -
(g - f)(-9) = g(-9) - f(-9)
= 
= 
= 
= -81.914
2). The relation is not a function because this function doesn't passes a vertical line test.
Last option will be the answer.