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boyakko [2]
3 years ago
9

Write the expression as a product of expressions.

Mathematics
1 answer:
scoray [572]3 years ago
8 0

Answer:

a^2(ab^{3}-b^{2}-c^{2})

Step-by-step explanation:

Given

a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}

Required

Factor

a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}

Factor out a^2

a^2(ab^{3}-b^{2}-c^{2})

<em>The expression cannot be further factored</em>

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A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
geniusboy [140]
Assuming that the balls are not replaced; 

\frac{6}{9}* \frac{5}{8}* \frac{4}{7}* \frac{3}{6}= 5/42 

(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one). 

Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42. 

Hope I Helped :) 

4 0
4 years ago
Help please!<br> 6x^2+2x-9=0<br> A 6.4, -8.4<br> B 1.1, -1.4<br> C -2.2, 2.8<br> D -1.1, -1.4
Yakvenalex [24]
6x^2+2x-9=0\\\\a=6;\ b=2;\ c=-9\\\\\Delta=b^2-4ac\to\Delta=2^2-4\cdot6\cdot(-9)=220\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-2-\sqrt{220}}{2\cdot6}=\dfrac{-2-\sqrt{220}}{12}\approx-1.4\\\\x_2=\dfrac{-2+\sqrt{220}}{2\cdot6}=\dfrac{-2+\sqrt{220}}{12}\approx1.1

Answer: B. 1.1; -1.4.
6 0
3 years ago
Which of the following points is in the solution set of y&gt;x2+7x-14​
Lesechka [4]

Answer:

Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored. Equation at the end of step 1 : x2 - 7x - 14 = 0. Step 2 : Parabola, Finding the Vertex: 2.1 Find the Vertex of y = x2-7x-14

7 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
3 years ago
Which are counterexamples?<br> Look at the picture below. <br> Choose all that apply.
Flauer [41]

Answer:

x^4/(2x^6)

Explanation:

In the first example the division results in a radical, not a polynomial.

The remaining examples are not counter-examples (they do result in a polynomial)

8 0
3 years ago
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