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horrorfan [7]
2 years ago
12

What factor or factors may reduce risk? (5 points)

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
4 0
I know it is futures ivestments
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Suppose a group of x people rent a log cabin for $320 for a weekend in the mountains and plan to share the cost equally. If one
Zanzabum

320/16 - 1 = 19 ppl hope i helped


8 0
3 years ago
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Please help
vovikov84 [41]

Answer: 13

Step-by-step explanation: Pythagorean theorem,

a²+b²=c²

5²+12²=c²

25+144=c²

Square root of 169 is 13

Hope this helps you!!!

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3 years ago
How too solve for x 5x+8
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3 0
3 years ago
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Twice the sum of m and n.
Sholpan [36]

2(m+n) is the answer. The question is asking for the sum of m and n then multiplying that sum by 2                

3 0
3 years ago
Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice
Romashka [77]

Answer:

a)   S=50

    P(X)=0.02

b)  P(W,M,C)=8*10^-^6

c)  P(W_2_3)=1.18*10^-^3

Step-by-step explanation:

From the question we are told that

Sample space S=50

Sample size n=30

a)Generally the sample space S is

S=50

The probability measure is given as

P(X)=\frac{1}{50}

P(X)=0.02

b)

Generally the probability that  the class hangs Wisconsin’s flag on Monday, Michigan’s flag on Tuesday, and California’s flag on Wednesday is mathematically given as

Probability of each one being hanged is

P(X)=\frac{1}{50}

Therefore

P(W,M,C)=\frac{1}{50} *\frac{1}{50}* \frac{1}{50}

P(W,M,C)=\frac{1}{125000}

P(W,M,C)=8*10^-^6

c)Generally the probability that Wisconsin’s flag will be hung at least two of the three days is mathematically given as

Probability of two days hung +Probability of three days hung

Therefore

P(W_2_3)=^3C_2 (1/50) * (1/50) * (49/50) +^3C_3 (1/50) * (1/50) *(1/50)

P(W_2_3)=148 / 125000

P(W_2_3)=1.18*10^-^3

3 0
3 years ago
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