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thus the given equation is a linear equation in two variables ...
thus ploting a table we get as ...
y = -5x + 3
there fore
1) at y=0 , x = 3/5 .... 0 = -5x +3
= -5x = -3 ..thus X = 3/5
2) at x=0 , y= 3 ...
y = -5 (0) + 3 = 3
3) at X =1 , y = -2
4) at y=1 , x = 2/5
30÷5=6
4×5=20
for every 30 green lights there are 20 white lights
If i read it right, it would just be 1 - 953. Depending on your grade (Around 3rd grade it would just be 952) Above that would be -952
Answer:
p=0.25
Step-by-step explanation:
Given that a club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officers, and their designated positions within the club are President (P), Vice dash President (Upper V )comma Secretary (Upper S )comma nbspand Treasurer (Upper T ).
Sample space would be
a){ {P}, {V}, {S} {T}} is the sample space with notations standing for as given in the question
b) Each sample is equally likely. Hence we have equal chances for selecting any one out of the four.
If probability of selecting a particular sample of size I is p, the by total probability axiom we have
\begin{gathered}4p =1\\p =0.25\end{gathered}
4p=1
