Which of the following is equal to 250 milliliters?

PLEASE HELP. i need to show my work for<br> the correct answer. please help

e-lub [12.9K]

Answer:

I THINK IM WRONG BUT

Step-by-step explanation:

X3 NUZZELS POINCES ON U

7 0

3 years ago

Ariel wrote a total of 4 pages over 2 hours. How many hours will Ariel have to spend writing this week in order to have written

Pachacha [2.7K]

Your answer is 1

Step-by-step explanation:

4=2

8=?

4÷8×2

=1

3 0

2 years ago

Ok but listen to streets by doja cat and vibeU-U

belka [17]

Answer:

aNd?

tHeREs mORe..

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me with my review please

Marianna [84]

Answer:

I believe it is AAS but I'm not 100% so if I'm wrong I would like to apologies ahead of time.

I hope this is good enough:

4 0

2 years ago

Please help me i need to find the area of shaded region please help me

Montano1993 [528]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=13\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)\\A=84-24\\A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)\\A=96-16\\A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)\\A=80+16\\A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)\\A=225-81\\A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(4)(2)\\A=21-8\\A=13\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)\\A=(49\pi -33)\ in^2$

6 0

3 years ago