Question

Find the vertices and foci of the hyperbola.y2 − x2 = 9vertices (x, y) = (smaller y-value)(x, y) = (larger y-value)foci (x, y) = (smaller y-value)(x, y) = (larger y-value)

Answer 1

Answer:

Step-by-step explanation:

Given is a hyperbola as

$y^2-x^2 =9\\\frac{y^2}{9} -frac{x^2}{9}=1$

This is of the std form where a=b=3

Hence vertices are

$(x,y) =(3,-3) and (3,3)$

Foci =( ±ae,0)

=(±$\sqrt{a^2+b^2} ,0)$

=(±$2\sqrt{3} ,0)$