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andrew-mc [135]

3 years ago

8

Mr.Adams divided 223 markers equally among 26 students in his class.He puts the extra markers in a box. What is the least number

ofrece markers he puts in the box?

1 answer:

Reil [10]3 years ago

3 0

Fifteen because 208/26 = 8 and 223 - 208 = 15

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9 (9m+3t)=<br> simplify pls

Aleks04 [339]

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Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

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$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

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Please refer to the attachment

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