Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
56, because you times 7 by 2 because Greg has 2 then you times 7 by 10 because then you get the answers 14 and 70 and take them away from each other
Answer:
10.05
Step-by-step explanation:
9.99+9.99+9.99+14.99+14.99
=59.95
70-59.95
=10.05
Using conditional probability, it is found that there is a 0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.
<h3>What is Conditional Probability?</h3>
- <em>Conditional probability</em> is the <u>probability of one event happening, considering a previous event</u>. The formula is:
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem, the events are:
- Event A: Patient has Medicare.
- Event B: Patient has Medicaid.
For the probabilities, we have that:
- 35% of the patients have Medicare, hence
.
- Of those who have Medicare, there is a 10% chance they also have Medicaid, hence
.
Then, applying the <em>conditional </em>probability:
0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.
You can learn more about conditional probability at brainly.com/question/14398287
