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Setler79 [48]
3 years ago
14

X = y2 - 1

Mathematics
1 answer:
MissTica3 years ago
5 0

Answer:

Option (2) is correct.

2y^2-y-6=0

Step-by-step explanation:

Given two equations x=y^2-1 and 2x-y=4

We have to choose an equation from the given options which could be the result of using substitution to solve the system.

Since the given equation is in term of y , so we make substitution of x in term of y.

From 2x-y=4,

⇒ x=\frac{4+y}{2}

Substitute  x=\frac{4+y}{2}  in other equation x=y^2-1

We get, x=y^2-1 \Rightarrow \frac{4+y}{2}=y^2-1

Cross multiply we get,

\Rightarrow {4+y}=2y^2-2

Solving further, we get

\Rightarrow 2y^2-y-6=0

Thus, option (2) is correct.

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Answer:

tfbgf

Step-by-step explanation:

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3 years ago
Will mark brainliest and 25 points please help c:
ValentinkaMS [17]
Third angle = 180 - (44 + 72) = 180 -  116 = 64 degrees answer
3 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
On the first day of the fiscal year, Shiller Company borrowed $85,000 by giving a seven-year, 7% installment note to Soros Bank.
Lera25 [3.4K]

Answer

A₁ - Journal entry at the time of issue of installment note for cash:

Bank A/c                              Dr           $85,000

To Notes Payable               Cr           $85,000

A₂– Journal entry at the time of first annual payment:

Notes Payable A/c           Dr           $9,822

Interest Expense A/c       Dr           $5,950

To Bank A/c                   Cr                            $15,772

Notes payable to be reported in balance sheet at the end of fiscal year:

Notes payable end balance = $85,000 - $9,822 = $75,178

Interest for 2nd year = $75,178 * 7% = $5,262

Installment amount for 2nd year = $15,772  

Principal repayment for 2nd year = $15,772 - $5,262 = $10,510

Therefore out of $75,178 notes payable, $10,510 is payable within 1 year.

There $10510 will be shown in balance sheet as current liabilities and

remaining $64,668 will be shown in balance sheet as long term liability.

5 0
3 years ago
Help and dont guess or ill report
Alex17521 [72]

Answer:

11 lessons +2/5th of a lesson

Step-by-step explanation:

360-85= 285

285/25 = 11.4

Answer is 11 lessons and 2/5th of a lesson

4 0
3 years ago
Read 2 more answers
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