In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.
1 answer:
Check the picture below.
keeping in mind that the diagonals in a rhombus always meet at right-angles, thus all angles at point O are all right-angles.
now, notice that the AC angle bisector, cuts the angle at A in two equal halves, and if you look at the triangle BOC, there is a 15.5° angle, and a right-angle, and well, you already know what the last one is.
keeping in mind that the diagonals in a rhombus always meet at right-angles, thus all angles at point O are all right-angles.
now, notice that the AC angle bisector, cuts the angle at A in two equal halves, and if you look at the triangle BOC, there is a 15.5° angle, and a right-angle, and well, you already know what the last one is.
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Answer:
L = 15.53 ft
Step-by-step explanation:
using diagram which is attached below
now, using Pythagoras theorem
L² = b² + (5 + x)²...............(1)
using similarity of triangle
from equation (1)
for maxima or minima
x = -5 and x = ∛190 = 5.74
on second derivative 5.74 is the value which comes out to be minimal value which is the distance between the fence and ladder
now,
L² = 241.38
L = 15.53 ft
