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erastovalidia [21]
2 years ago
13

Pls help I cant do this

Mathematics
2 answers:
AlladinOne [14]2 years ago
8 0

Answer:

Here you go!

Step-by-step explanation:

Hope this helped!

mixer [17]2 years ago
5 0

Answer: a=7

d=2

Step-by-step explanation:

You might be interested in
Seven times the difference of x and 4 is -10
4vir4ik [10]

Answer:

In this equation x = 2

Step-by-step explanation:

First, it is easiest to convert these words to numbers. That would make it

4 - <em>x  </em>· 7 = -10

First subtract 4 from both sides.

4 - <em>x</em> · 7 - 4 = - 10 - 4

Then you simplify.

-<em>x ·</em> 7 = -14

Divide both sides by 7.

\frac{-x(7)}{-7} = \frac{-14}{-7}


Then you simplify that fraction to 2 and thats how you get your answer.



7 0
3 years ago
Tu went to the movies. He bought 2 tickets for $9.50 each, popcorn for $5.00 and 2 drinks for $4.25 each. He gave the clerk two
AnnyKZ [126]

Answer:

A

Step-by-step explanation:

A is the only equation that does not account for the fact that Tu bought 2 tickets and 2 drinks.

The rest do: B subtracts the appropriate amounts twice, C multiplies the doubled expenses, and D does the same, just the amount paid is also separated.

8 0
3 years ago
Read 2 more answers
What is the area of the following figure in square inches?
grin007 [14]

Answer:

umm

Step-by-step explanation:

13

7 0
2 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
Solve for d 4d &gt; 8 (Please help)
vekshin1

Answer:

d > 2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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