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garik1379 [7]
3 years ago
10

How do you solve the questions Plzzzzz I really need help

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

The answers are given in step-by-step explanation

Step-by-step explanation:

In question 4,

Elina walked 12 miles then she walked 0.25 that distance.

We have to find the distance she walked

Distance=12+0.25 of that distance

              = 12+0.25(12)

              = 12(1+0.25)=12\times 1.25=15 miles

Hence, A, B, and C are correct

In question 5,

Given circumference is 600 m

we have to find the good approximation area of circle

circumference = 600 m

2\pi \times r=600

\pi \times r=300 ⇒ r=95.49

Area of circle is \pi \times r^2

                       = (3.14)(95.49)^2=28631.587914m^2

Hence, the good approximation area of circle is 30,000 m^2

In question 6,

Given d=3t where d represents the distance between the snail and rock in inches and t represents the time in minutes.

Number 3 represents that distance between snail and certain rock is 3 times that of time.

given distance is 9 inches we have to find the time i.e d=3t ⇒ 9=3t ⇒ t=3 minutes.

Hence, will be 3 minutes when snail is 9 inches far from certain rock.

Now, times given 9 minutes we have to find the distance, d=3t=3(9)=27 inches.

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?• (-10) = 90<br> Please help I need it now
Ivan

Answer:

x = -9

Step-by-step explanation:

x • -10 = 90

x = 90/-10

x = -9

Hope this helped! <3

5 0
3 years ago
Read 2 more answers
Please help solve -2|5y-1|=-10
sweet-ann [11.9K]
Alright, so we can start by dividing -2 from both sides, getting |5y-1|=20. Then, since 5y-1 is in an absolute value, 5y-1 is either 20 or -20.
In 5y-1=20, we can add one to both sides, getting 5y=21 and y=21/5. In
5y-1=-20, we can add one again, getting 5y=-19 and y=-19/5.

If you have any more equations, make sure to plug both numbers in to check, but otherwise y has two answers , which are -19/5 and 21/5.
7 0
4 years ago
A number is divided by 3. Then 14 is added to the quotient. The result is 33. What is the orginal number?
seropon [69]

let "a number" = x

a number is divided by 3 => x/3

14 is added to the quotient => (x/3) + 14

The result is 33 => " = 33"

Solve for x

(x/3) + 14 = 33

Isolate the x. Note the equal sign. What you do to one side you do the other.

Subtract 14 from both sides

(x/3) + 14 (-14) = 33 (-14)

x/3 = 19

Isolate the x. Multiply 3 to both sides

x/3(3) = 19(3)

x = 19(3)

x = 57

57 is your original number

hope this helps

4 0
3 years ago
A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day
-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

A(t) = A(0)e^{-kt}

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

A(t) = A(0)e^{-0.1392t}

Find the substance's half life, in days.

This is t for which A(t) = 0.5A(0). So

A(t) = A(0)e^{-0.1392t}

0.5A(0) = A(0)e^{-0.1392t}

e^{-0.1392t} = 0.5

\ln{e^{-0.1392t}} = \ln{0.5}

-0.1392t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.1392}

t = 4.98

The substance half-life is of 4.98 days.

5 0
3 years ago
Enter the value, as a mixed number in simplest form, in the box. |2 1/3| = ?
Fittoniya [83]
Unclear of the question, but the value is already as a mixed fraction. The value of absolute value is just the distance from zero. So, |-4|=4 or |6|=6
|2 \frac{1}{3} |  =  2 \frac{1}{3}
7 0
3 years ago
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