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3 years ago

. The diameter of Bubba's bubble is

Mathematics

1 answer:

Oksana_A [137]3 years ago

8 0

Answer:

10.22

Step-by-step explanation:

2.45 * 10 =20.45 - 3.67 * 10 =30.67

30.67 - 20.45

30 - 20 = 10

.67 - .45 = .22

30.67 - 20.45 = 10.22

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I’ll give Brainliest answer for the right answer

lora16 [44]

Answer:

You may report me if you wish as long as you know i cared enough to write this for you

Step-by-step explanation:

I know i may be unwanted here but I just want you to know that you are incredible and that I love you for you! You are special to everyone you meet, and should not change who you are. I know your life may be tough, but you are strong and can get through it!

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2 years ago

A Norman window has the shape of a rectangle surmounted by a semicircle. Suppose the outer perimeter of such a window must

Feliz [49]

The base length that will maximize the area for such a window is 168.03 cm. The exact largest value of x when this occurs is 233.39 cm

Suppose we make an assumption that:

(x) should be the width of the rectangle base;
(h) should be the height of the rectangle

Also, provided that the diameter of the semi-circle appears to be the base of the rectangle, then;

the radius $\mathbf{r = \dfrac{x}{2}}$

and, the perimeter of the window can now be expressed as:

$\mathbf{x + 2h + \pi r = x + 2h + \dfrac{\pi x }{2}}$

$\mathbf{= \Big ( 1 + \dfrac{\pi}{2}\Big) x + 2h}$

Given that the perimeter = 600 cm

∴

$\mathbf{ \Big ( 1 + \dfrac{\pi}{2}\Big) x + 2h= 600}$

$\mathbf{ h = 300 - \Big( \dfrac{1}{2} + \dfrac{\pi}{4}\Big) x}$

Since h > 0, then:

$\mathbf{ h = 300 - \Big( \dfrac{1}{2} + \dfrac{\pi}{4}\Big) x>0}$

By rearrangement and using the inverse rule:

$\mathbf{ x< \dfrac{ 300}{\Big( \dfrac{1}{2} + \dfrac{\pi}{4}\Big) } }$

$\mathbf{ x= \dfrac{ 1200}{\Big( 2 +\pi \Big) } }$

$\mathbf{ x= 233.39 \ cm }$

Thus, the largest length x = 233.39 cm

However, the area of the window is given as:

$\mathbf{A(x) = xh + \dfrac{1}{2} \pi r^2}$

$\mathbf{A = x \Big [ 300 - \Big ( \dfrac{1}{2}+\dfrac{1}{4} \Big) x \Big ] +\dfrac{1}{2}\pi \Big(\dfrac{x}{2} \Big )^2}$

$\mathbf{A (x) = 300x - \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big) x^2 \ cm^2}$

Now, at maximum, when the area A = 0. Taking the differentiation, we have:

$\mathbf{\dfrac{d}{dx} 300x - \dfrac{d}{dx} \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big) x^2 \ =0}$

$\mathbf{ 300 - 2x \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big) \ =0}$

Making x the subject of the formula, we have:

$\mathbf{x = \dfrac{1200}{4 +\pi}}$

x = 168.03 cm

Taking the second derivative:

$\mathbf{\dfrac{d}{dx} \Big [300 -2x \Big( \dfrac{1}{2} + \dfrac{\pi}{8}\Big) \Big]}$

$\mathbf{= -2 \Big( \dfrac{1}{2}+\dfrac{\pi}{8}\Big )$

Therefore, we can conclude that the maximum area that exists for such a window is 168.03 cm

Learn more about derivative here:

brainly.com/question/9964510?referrer=searchResults

6 0

3 years ago

The following equation is true for all values of x. Write the number that completes the equation. Show your work.

labwork [276]

5y+2(3y-1)=__y-(y+2)
5y+6y-2=__y-y-2
11y-2+2+y=__y
12y=___y
so 12

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3 years ago

Write the numbers three hundred and fifty-four thousand, two hundred and ten in figures (354,210).

GalinKa [24]

Answer:

Three hundred and fifty-four thousand, two hundred and ten =354210

Hundred thousand║Ten thousand║Thousand║Hundred║Tens║Ones

3 5 4 2 1 0

Step-by-step explanation:

6 0

2 years ago

Determine whether the given value is a solution of the equation.<br> 7w = 73; w = 10

kipiarov [429]

Step-by-step explanation:

When w=10, 7w=7×10=70

But the given value of 7w is 73.

So, the given value is not a solution of the equation.

8 0

3 years ago