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3 years ago

Here are two rational numbers 7/25 and 3/10

Mathematics

2 answers:

anzhelika [568]3 years ago

6 0

$\frac{7}{25}=\frac{28}{100}$

$\frac{3}{10}=\frac{30}{100}$

$\frac{29}{100}$ Answer

ira [324]3 years ago

3 0

7/25->14/50->28/100
3/10->15/50->30/100
Answer will be 29/100

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It is estimated that there are 828 motor vehicles in the US it is estimated that there are 828 Motor vehicles in the US for ever

coldgirl [10]

Answer:

314 million

Step-by-step explanation:

Given that :

Number of motor vehicle in the U.S for every 1000 people = 828

If the number of motor vehicle in the United States = 260 million

Then,

Let x = number of people Given number of vehicles = 260,000,000

1000 people = 828 vehicles

x = 260,000,000

828x = (260,000,000 * 1000)

828x = 260,000,000,000

x = 314009661. 835

x = 314 million (approx)

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3 years ago

A friend gives you a recipe for a birthday cake. The recipe states you need 12 ounces of flour. You have a 500 g bag of flour, d

bagirrra123 [75]

Yes, you have enough flour.

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3 years ago

Make x the subject of the formula x(a-b)=a(b-x).

ddd [48]

Answer:

Hello,

Step-by-step explanation:

$x(a-b)=a(b-x)\\\\x(a-b)=ab-ax\\\\x(a-b)+ax=ab\\\\x(a-b+a)=ab\\\\x(2a-b)=ab\\\\\\x=\dfrac{ab}{2a-b} \ if\ 2a-b\neq 0$

3 0

2 years ago

Read 2 more answers

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg

Harman [31]

Answer:

$x=\frac{-5(+/-)\sqrt{5}} {2}$

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$f(x)=x^{2} +5x+5$

equate the function to zero

$x^{2} +5x+5=0$

$a=1\\b=5\\c=5$

substitute in the formula

$x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}$

$x=\frac{-5(+/-)\sqrt{5}} {2}$

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

6 0

3 years ago

Read 2 more answers

Find two positive consecutive odd integers whose products is 99.

tensa zangetsu [6.8K]

Answer:

9,11

Step-by-step explanation:

let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)

therefore;

x(x+2)= 99

x²+2x=99

I usually solve the sum like this,

we need to find the nearest square number ( number smaller than the number on the R.H.S)

here, it is 81, whose square root is 9. therefore the solution is 9

verification:

(9)²+2*9=99

81+18=99

99=99

hence, 9 is the solution. therefore the positive odd consecutive integers are

x=9

x+2=9+2= 11

verification:

9*11=99

99=99

L.H.S=R.H.S

5 0

3 years ago