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djyliett [7]
4 years ago
10

Here are two rational numbers 7/25 and 3/10

Mathematics
2 answers:
anzhelika [568]4 years ago
6 0
\frac{7}{25}=\frac{28}{100}

\frac{3}{10}=\frac{30}{100}

\frac{29}{100} Answer
ira [324]4 years ago
3 0
7/25->14/50->28/100
3/10->15/50->30/100
Answer will be 29/100
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maw [93]

Answer: 84 ft

Step-by-step explanation:

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3 years ago
Find the measure of missing angles.<br> A=<br> B=<br> C=
vlada-n [284]

Answer:

A = 140°

B = 40°

C = 140°

Step-by-step explanation:

1. Since we know that opposite angles are equal, b = 40°

2. Since we also know that the angle of a line adds to 180°,

a = 180° - 40°

So, 140°

Then repeat step 1 to find C through A.

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What 11/5 cubic feet = to?
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Answer:

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Step-by-step explanation:

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What's is 66tens-30tens?
gizmo_the_mogwai [7]
36 tens or 360 is the answer.
8 0
3 years ago
A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =
AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have \mu = 43, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 43}{4}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0
3 years ago
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