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Illusion [34]
4 years ago
6

Yoshi and Rana serve muffins. There are 3 muffins with nuts. 1/6 of the muffins have nuts. How many muffins do they serve in all

?
Mathematics
2 answers:
schepotkina [342]4 years ago
6 0
1/6 of the muffins is 3 muffins with nuts. So you multiply 3 by 6 to get 18 muffins in all.

Airida [17]4 years ago
5 0
It's would probably be 3 1/6
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Find the area of the irregular figure.
Diano4ka-milaya [45]

Answer:

The area of the irregular figure is  366 cm sq.

Step-by-step explanation:

This irregular figure is made of 1 Rectangle +  1 right Triangle

<u>Area of the Rectangle:</u>

Length of the rectangle = 21 cm,

Width of the rectangle  = 14 cm

AREA of Rectangle =  LENGTH x WIDTH

          =  21 cm x 14 cm =  294 sq cm

⇒Area of the Rectangle  =   294 sq cm   ..... (1)

<u>Area of the Right Triangle:</u>

Base of the rectangle = 16 cm,

Height of the rectangle  = 21 cm -  12 cm = 9 cm

AREA of Right Triangle =  \frac{1}{2}  \times B \times H

          = \frac{1}{2} \times 16 \times 9 = 72

⇒Area of the Right Triangle   =   72 sq cm   ..... (2)

Now, area of the irregular figure  = Area of the( Rectangle  +Right Triangle)

= 294 sq cm + 72 sq cm = 366 cm sq

Hence, the area of the irregular figure is  366 cm sq.

6 0
3 years ago
Which kind of triangle exists if the side measures are 3, 9, and 10?
Illusion [34]

Step-by-step explanation:

    There is a rule that if c^2 > a^2 + b^2, then it is an obtuse triangle.

    *c is the longest side

     I attached more information on it below.

3 0
3 years ago
Simplify the radical using the imaginary number i.<br> a) sqrt-144 = <br> b) sqrt-360 =
8090 [49]

Answer:

sgsgzhzhdhenovavjejvoogjqou2jgjqhj

Step-by-step explanation:

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8 0
3 years ago
What is the vertex for the function f(x) = 3(x – 2)2 + 4?
Gala2k [10]

Answer:

The vertex for the function f(x) = 3(x – 2)2 + 4 is at (2, 4).

Step-by-step explanation:

Find the vertex for f(x) = 3 (x - 2)^2 + 4

f(x) = 3 (x - 2)^2 + 4 can also be written as:

y = 3 (x - 2)^2 + 4

To find critical points, first compute f'(x):

d/(dx)(3 (x - 2)^2 + 4) = 6 (x - 2):

f'(x) = 6 (x - 2)

Solve 6 (x - 2) = 0

6x - 12 = 0

6x = 12

x = 2

iI you substitute x = 2 in 3 (x - 2)^2 + 4 then you get:

y = 3 (x - 2)^2 + 4

x = 2

y = 3 (2 - 2)^2 + 4

y = 3 (0)^2 + 4

y = 3 (0) + 4

y = 4

Answer: The vertex for the function f(x) = 3(x – 2)2 + 4 is at ( 2, 4 ).

5 0
3 years ago
9. Write an equation parallel to y = 2x + 4that<br> passes through the point (-4,-1).
sasho [114]

Answer:y=2x+7

Step-by-step explanation:

so for the new equation, we know the slope is going to be the same (because its parallel) so for starters we have y=2x+b so now in order to find b (the y-intercept) we have to plug the point into the equation. So it would look like -1=2(-4)+b and then you solve for b and get 7 for b. SO the final answer is y=2x+7.

6 0
3 years ago
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