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AlladinOne [14]
3 years ago
6

In triangle ABC, it is given that A = 70 degree, B = 52 degree, BO and CO are the bisectors of angle B and angle C

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

angle ocb=58°

angleboc=96°

Step-by-step explanation:

first get the measure of angle acb which is 58°

this is becoz the total angles in a triangle add up to 180°

angle cbo =26° and angle bco=58°

therefore to get the remaining angle boc ,u add 58 &26 ,then minus from 180

the answer is 96°

natta225 [31]3 years ago
6 0

Answer:

Angle OCB= 35 degrees and Angle BOC= 119

Step-by-step explanation:

ANGLE OCB= 1/2 C (Construction of bisector)

= 1/2 70

= 35

ANGLE OBC= 1/2 B (Construction of bisector)

= 1/2 52

= 26

Therefore, in triangle BOC,

180 degree= ANGLE OBC+ANGLE BOC+ANGLE OCB

180= 35+26+ANGLE BOC

180= 61+ANGLE BOC

ANGLE BOC= 180-61

ANGLE BOC= 119

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I really need help with this!!!
netineya [11]
2 because is isisisisisisisisis
5 0
3 years ago
What is an equation of the line that passes through the point (1,-3) and is perpendicular to the line x+3y=21
docker41 [41]

The linear equation that is perpendicular to the line x+3y=21 is:

y = 3*x - 6

<h3>How to find the equation of the line?</h3>

A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

x +3y = 21

3y = 21 - x

y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

m*(-1/3) = -1

m = 3

our line is:

y = 3*x + b

To find the value of b, we use the fact that our line passes through (1, - 3)

-3 = 3*1 + b

-3 - 3 = b

-6 = b

The line is y = 3*x - 6

Learn more about linear equations:

brainly.com/question/1884491

#SPJ1

3 0
1 year ago
What is the greatest common factor of 31 43 and 95?
kramer
It’s 1. Apparently my answer is not long enough so I’m making it longer :(:
7 0
3 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
2 years ago
Sorry to bother you, but I am STUGGLYINGGG
Y_Kistochka [10]
I think the answer is a
6 0
2 years ago
Read 2 more answers
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