An irregular parallelogram rotates 360° about the midpoint of its diagonal. How many times does the image of the parallelogram c
oincide with its preimage during the rotation?
A.2
B.4
C.6
D.8
A.2
B.4
C.6
D.8
1 answer:
Answer:
The correct options is A.
Step-by-step explanation:
The each diagonal of an irregular parallelogram divides the parallelogram in two equal and congruent parts. The diagonal bisects each other.
It means, if a irregular parallelogram rotates 180° about the midpoint of its diagonal, then the image of the parallelogram coincide with its preimage during the rotation.
If a irregular parallelogram rotates 360° about the midpoint of its diagonal, then the image of the parallelogram coincide 2 times with its preimage during the rotation.
Therefore the correct option is A.
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Answer:
The correct option is;
No, the distance from (0, 0) to (2, √6) is not 3 units
Step-by-step explanation:
The given parameters of the question are as follows;
Circle center (h, k) = (0, 0)
Point on the circle (x, y) = (3, 0)
We are required to verify whether point (2, √6) lie on the circle
We note that the radius of the circle is given by the equation of the circle as follows;
Distance² = (x - h)² + (y - k)² = r² which gives;
(3 - 0)² + (0 - 0)² = 3²
Hence r² = 3² and r = 3 units
We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;
Therefore;
(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²
Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10
Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point (2, √6), does not lie on the circle.