Answer:
1.03mole
Explanation:
Given parameters:
Pressure = 0.884 atm
Temperature = 6°C = 273 + 6 = 279k
Volume = 26.5L
Unknown:
Number of moles = ?
Solution:
To solve this problem, we use the ideal gas equation:
PV = nRT
P is the pressure
V is the volume
n is the number of moles
R is the gas constant = 0.082atmdm³mol⁻¹K⁻¹
T is the temperature
n = 
= 
= 1.03mole
Answer:
P₂ = 0.205torr
Explanation:
Boyle's law relates the pressure and volume of a gas under two different conditions. The equation is:
P₁V₁ = P₂V₂
<em>Where P is pressure and V volume of of 1, initial conditions and 2, final conditions.</em>
P₂ is our incognite
Replacing:
P₁V₁ = P₂V₂
8.20x10⁴torr*15.0L = P₂*600x10⁴L
<h3>P₂ = 0.205torr</h3>
<em />
Answer:
- 0.674 kJ.
Explanation:
The equation used to solve this problem is:
Q = mCΔT
where,
Q = amount of heat
m = mass of the substance
C = specific heat capacity
ΔT = change in temperature
= Temp.f - Temp.i
Given:
m = 29.2 g
Temp.i = 79°C
Temp.f = 27°C
Cp(iron) = 0.444 J/g.K
Q = mCΔT
ΔT = 27.0°C - 79.0°C
= -52°C
= 29.2 * 0.444 * -52
Q = - 674.17 J
= 0.674 kJ.
I can deduce here that the best that describes my choice is: It’s my best explanation for now, but I really would have to test my idea to be sure.
<h3>What is choice?</h3>
Choice actually refers to the act of choosing between two or more things. It has to do with going with the option, idea, decision, product or something that one prefers.
When we make choices, it depicts what we actually want. Some people still make wrong choices. The choices people make can either make or mar them in the present or future.
Looking at the given question, my choice is actually the first option.
It's clear that the idea hasn't been tested in order to be sure though it's has the best explanation.
Learn more about choice on brainly.com/question/6947486
#SPJ1
Answer:
328 ml
Explanation:
We have given final volume =575.2 ml=0.575 L
Final concentration = 0.8012 M
We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles
We have to find initial volume
So initial volume 
