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2 years ago

If the following weights have masses of 2, 4, 6 and 8 kg,

Chemistry

1 answer:

Marrrta [24]2 years ago

6 0

Answer:

8 kg mass

Explanation:

As we can see in the image the weight of mass 8 kgs has a large surface area as compared to the surface area of other masses. In general, it has been observed that a wide surface area has more surface particle for heat conduction. Hence, the rate of heat transfer is directly proportional to the surface area of heat conducting surface. Thus, the larger the surface area, the faster is the rate of heat conduction.

Hence, weight of mass 8Kg wil transfer heat a fast rate.

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Simora [160]

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2 years ago

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Many atomic dimensions are expressed in angstroms (A). (1A = 1 x 10-8cm). What is the angstrom equal to in terms of the SI units

Nataly [62]

Answer:

1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

Explanation:

Angstrom is the unit of the length which is equal to one ten-billionth of the metre or 10⁻¹⁰ m. It is represented by the symbol is Å .

Angstrom is not part of SI system of the units, but it is considered as a part of metric system.

Angstrom is used often in natural sciences as well as technology in order to express the sizes of atoms / molecules, and the lengths of the chemical bonds, etc.

1 Å = 10⁻¹⁰ m

1 nm = 10⁻⁹ m

1 pm = 10⁻¹² m

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1 Å = 1.0 × 10⁻¹ nm

1 Å = 1.0 × 10² pm

7 0

3 years ago

What is the maximum number of grams of copper that could be produced by the reaction of 30.0 of copper oxide with excess methane

Solnce55 [7]

Answer: 24.13 g Cu

Explanation:

<u>Given for this question:</u>

M of CuO = 30 g

m of CuO = 79.5 g/mol

Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol

= 0.38 mol

The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:

CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)

The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side

4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)

From the stoichiometry of the balanced equation:

4 moles of CuO gives 4 moles of Cu

1 mole of CuO gives 1 mol of Cu

0.38 mol of CuO gives 0.38 mol of Cu

Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu

= 0.38 × 63.5 g

= 24.13 grams

Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane

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1 year ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−