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Arte-miy333 [17]
3 years ago
9

Calculate the following quantity: volume of 1.403 M copper(II) nitrate that must be diluted with water to prepare 575.2 mL of a

0.8012 M solution.
Chemistry
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

328 ml

Explanation:

We have given final volume =575.2 ml=0.575 L

Final concentration = 0.8012 M

We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles

We have to find initial volume

So initial volume =\frac{moles\ of \ copper(II)\ nitrate}{initial\ concentration}=\frac{0.4606}{1.403}=0.328L=328ml

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What is the frequency of an X-ray that has a wavelength of 1.5 x 10 -9 m? The speed of electromagnetic radiation is 3.0 x 10 8 m
AlexFokin [52]

Answer:

2.0x10¹⁷ Hz is the frequency of the X-ray

Explanation:

We can find the frequency of a wave of energy from the wavelenght and its speed using the formula:

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<em>λ is the wavelength in meters = 1.5x10⁻⁹m</em>

<em>And f is the frequency in s⁻¹ = Hz</em>

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3 0
2 years ago
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Masja [62]

Answer:

0.0745 mole of hydrogen gas

Explanation:

Given parameters:

Number of H₂SO₄ = 0.0745 moles

Number of moles of Li = 1.5107 moles

Unknown:

Number of moles of H₂ produced = ?

Solution:

To solve this problem, we have to work from the known specie to the unknown one.

The known specie in this expression is the sulfuric acid,  H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.

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 From the balanced equation;

     

Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.

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But we were given 0.0745 moles,

This suggests that the limiting reagent is the sulfuric acid because it is in short supply;

   

   since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;

    0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas

4 0
3 years ago
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