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allsm [11]
3 years ago
8

The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40, 40, 48, 61, 72,

78, 84, 84, 76, 65, 54, 42
Select the correct answer below:
A) Sample minimum: 42, Sample maximum: 78
Q1: 45, Median: 63, Q3: 77
B) Sample minimum: 40, Sample maximum: 84
Q1: 45, Median: 63, Q3: 77
C) Sample minimum: 40, Sample maximum: 42
Q1: 54.5, Median: 81, Q3: 70.5
D) Sample minimum: 40, Sample maximum: 84
Q1: 40, Median: 61, Q3: 76
Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

Step-by-step explanation:

The first step is to write the temperatures in crescent order:

40, 40, 42, 48, 54, 61, 65, 72, 76, 78, 84, 84,

The sample minimum is the lowest value = 40

The sample maximum is the highest value = 84.

Since there are 12 numbers, the sample median is the average between the 6th and 7th terms:

M = \frac{61+65}{2}\\ M=63

The first quartile is the average between the 3rd and 4th terms:

Q_1 = \frac{42+48}{2}\\ Q_1=45

The third quartile is the average between the 9th and 10th terms:

Q_3 = \frac{76+78}{2}\\ Q_3=77

Therefore, the answer is:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

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Sang Jin has only quarters and nickels in her piggy bank. She has 66 coins in the bank with a value of $11.50.
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Your answer is 41 quarters.

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3 years ago
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Perform the multiplication. Simplify the answers. 2 √30*( √5+ √6+ √10+ √15)
Delicious77 [7]

The simplified expression of 2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})is 10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

The expression is given as:

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})

Expand the expression

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2\sqrt{30} \times \sqrt5+  2\sqrt{30} \times \sqrt6+  2\sqrt{30} \times \sqrt{10} +  2\sqrt{30} \times \sqrt{15}

Factor out 2

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{30} \times \sqrt5+  \sqrt{30} \times \sqrt6+  \sqrt{30} \times \sqrt{10} +  \sqrt{30} \times \sqrt{15})

Combine the radicals

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{150} +  \sqrt{180}+  \sqrt{300} +  \sqrt{450})

Expand the expression

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{25 \times 6} +  \sqrt{9 \times 20}+  \sqrt{100 \times 3} +  \sqrt{225\times 2})

Evaluate the roots

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(5\sqrt{6} +  3\sqrt{20}+  10\sqrt{3} +  15 \sqrt{2})

Expand

2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) =10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

Hence, the simplified expression of 2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})is 10\sqrt{6} +  6\sqrt{20}+  20\sqrt{3} +  30\sqrt{2}

Read more about simplified expressions at:

brainly.com/question/8008182

3 0
2 years ago
the power generated by an electrical circuit (in watts) as a function of its current C (in amperes) is modeled by P(c)= -15c(c-8
katen-ka-za [31]

Answer:

c = 4 A

Step-by-step explanation:

The given function P(c) = - 15 c (c-8) is actually quadratic function:

P(c) = - 15c² + 120c    or parabola

The standard form of a quadratic function is:

y = ax² + bx + c

For which x is the maximum of the parabola we can find with this formula

x = - b/2a

in this case a = -15 and b = 120 and input variable is current c

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c = 4 A

God with you!!!

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Answer:

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Step-by-step explanation:

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Answer:

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I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...

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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:

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  3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses

  3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms

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Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...

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  d = (-15)^2 -4(3)(12) = 225 -144 = 81

This positive value means the equation has 2 real solutions.

4 0
3 years ago
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