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bixtya [17]
3 years ago
9

A soccer team played 32 games.If they won 25% of them, how many games did the team win

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
6 0

Answer:

They won 8 out of 32 games... i think, ill edit it if there is a problem

Step-by-step explanation:

32 x 25% = 8

or

32 x 0.25 = 8

Either one works.

Molodets [167]3 years ago
3 0

Answer:

8

Step-by-step explanation:

They only won 25%

25%=1/4

32/4=8

They won 8 games

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the parabola can be written as:

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first step.

find the vertex at:

x  = -b/2a

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now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.

The next step is to see if we have real roots by using the Bhaskara's equation:

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Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.

If you do not have any real roots, you can feed into the parabola some different values of x around the vertex

for example at:

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8 0
3 years ago
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dolphi86 [110]
The larger the number of simulations the more likely are the results to be closest to those predicted by the probability theory.

When large number of simulations are run, some results might be higher than the results of probability theory, some results might be lower than the results of the probability theory and some might be exactly the same. So the average of all these results will be close to the results of Probability Theory. Thus, more the number of simulations, greater is the chance that the results are closer to those of simulation theory.

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Step-by-step explanation:

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3 0
3 years ago
Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

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2x+50=180

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x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

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\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0
3 years ago
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