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4 years ago

5

If 3/4 gallon of paint covers 1/3 of the wall then how much paint is needed for the entire wall

2 answers:

kykrilka [37]4 years ago

5 0

2 1/4 gallons of paint to cover the entire wall

natima [27]4 years ago

4 0

Answer:

9/4 or 2 and 1/4 gallons

Step-by-step explanation: You multiply by 3 to cover the entire wall.

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For the graph x = -3 find the slope of a line that is parallel to it.

slava [35]

We have that

the slope of the line that is parallel to x=-3 is classified as undefined.

<span>let's check the answer
</span><span>1) take any two points of the line x = -3
</span>point A (-3,0) point B (-3,5)
2) find the slope of the line x=-3
m=(5-0)/(-3+3)=5/0----------> is undefined

the answer is the option undefined

5 0

4 years ago

HELPPPPP IF U HAVE DONE THIS ASSIGNMENT B4

lianna [129]

Answer:

hope this will help you......

7 0

3 years ago

Read 2 more answers

6A. make a box and whiskers plot for the following data label the extrems,quartites class score 40,30,75,82,90,25,80,46

Aliun [14]

<span> 25 30 35 40 46 60.5 75 80 81 82 90
min Q1 Q2/med Q3 max
81-35=46=Interquartile range

</span><span>Is that all the information you wanted?</span>

5 0

3 years ago

Simplify (3a^4-2a^2+5-10)-(2a^4+4a^2+5a-2)

katrin [286]

Answer:

Step-by-step explanation:

3a^4 -2a^2 + 5 - 10 -(2a^4 +4a^2 + 5a -2)

as given.. i'm wondering if the 5 in the first group is really 5a.. hmmm

I'm guessing that it is... soooo distribute the minus sign

= 3a^4 - 2a^2 +5a -10 -2a^4 -4a^2 -5a +2

= a^4 -6a^2 -8 :) voila that's your answer

7 0

3 years ago

Make use of structure. For rectangle ABCD, two vertices are A(-2, 3) and B(4, 6). Find the slopes of BC, CD, and DA. Explain you

MrRissso [65]

We are given a rectangle ABCD

A(-2, 3)

B(4, 6)

We are asked to find the slopes of sides BC, CD, and DA.

Let me first draw a rectangle to better understand the problem

Recall that the slope is given by

$m=\frac{y_2−y_1}{ x_2−x_1}$ $\text{where}(x_1,y_1)=(-2,3)\text{and}(x_2,y_2)=(4,6)$

So the slope of side AB is

$m_{AB}=\frac{6-3}{4-(-2)}=\frac{3}{4+2}=\frac{3}{6}=\frac{1}{2}=0.5$

The sides BC and DA are perpenducluar to the side AB.

So their slopes will be

$m_{BC}=m_{DA}=\frac{1}{-m_{AB}}$

Substituting the value of slope of AB

$m_{BC}=m_{DA}=\frac{1}{-0.5}=-2$

The side CD is parallel to the side AB.

Parallel sides have equal slopes so

$m_{CD}=m_{AB}=\frac{1}{2}$

Therefore, the slopes of the rectangle ABCD are

$\begin{gathered} m_{AB}=m_{CD}=\frac{1}{2} \\ m_{BC}=m_{DA}=-2 \end{gathered}$

3 0

1 year ago