<h3>given:</h3>
side= 1.1 inches
<h3>to find:</h3>
the volume of the given cube rounded to the nearest tenth.
<h3>solution:</h3>
![v = {a}^{3}](https://tex.z-dn.net/?f=v%20%3D%20%20%7Ba%7D%5E%7B3%7D%20)
![v = {1.1}^{3}](https://tex.z-dn.net/?f=v%20%3D%20%20%7B1.1%7D%5E%7B3%7D%20)
![v = 1.331 \: {in}^{3}](https://tex.z-dn.net/?f=v%20%3D%201.331%20%5C%3A%20%20%7Bin%7D%5E%7B3%7D%20)
![v = 1 .33 \: {in}^{3}](https://tex.z-dn.net/?f=v%20%3D%201%20.33%20%5C%3A%20%20%7Bin%7D%5E%7B3%7D%20)
<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cube</u><u> </u><u>is</u><u> </u><u>1.33</u><u> </u><u>cubic</u><u> </u><u>inches</u><u>.</u>
The formula is 700 - 100 - 75(n-1), where n is the number of months.
Answer:
A
Step-by-step explanation:
![(f-g)(x)=f(x)-g(x)\\=(x-2)-(x^2+3x-4)\\=x-2-x^2-3x+4\\=-x^2-4x+2\\](https://tex.z-dn.net/?f=%28f-g%29%28x%29%3Df%28x%29-g%28x%29%5C%5C%3D%28x-2%29-%28x%5E2%2B3x-4%29%5C%5C%3Dx-2-x%5E2-3x%2B4%5C%5C%3D-x%5E2-4x%2B2%5C%5C)
Therefore, answer is A.