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finlep [7]
3 years ago
12

Five gal of water are added to a pool each minute.

Mathematics
2 answers:
il63 [147K]3 years ago
8 0
It would take 16 minutes to fill up an 80 gal of water
HOPE THIS HELPS
Sedaia [141]3 years ago
8 0

Answer:

It would take 16 minuets to fill the pool with 80 gallons.

Step-by-step explanation:

Five gal of water are added to a pool each minute.

The number of minutes that must pass until the pool contains 80 gal of water will be = \frac{80}{5} =16 minutes.

So, it would take 16 minuets to fill the pool with 80 gallons.

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the area of square Garden is 625 metre square find its length its perimeter and find the cost of fencing it with 5 round at Rs 2
Mazyrski [523]

Answer:

Length=25m

Parameter=100m

5 round cost RS 12500

Step-by-step explanation:

The area of a square

=x²

According to the question the equation is

x²=625

x=√625

x=25

The parameter is

25×4

100 meter

So

1 meter costs 25

100 " " 25×100

2500

1 round = 100 meter

So

5 round cost 2500×5

12500

8 0
3 years ago
1- 1/4 + 2/5= please help
zlopas [31]

Answer:

1.15:)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the square root of 58?
Westkost [7]

Answer:

7.6

Step-by-step explanation:

6 0
3 years ago
3927283+8093<br> Help pls
Debora [2.8K]

Answer: 3935376

Step-by-step explanation: 3927283+8093

3935376

7 0
2 years ago
Read 2 more answers
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

(4x-1)ln(e) =ln(3)

ln e as an inverse simplifies to 1.

(4x-1)(1)=ln(3)

We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
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