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weeeeeb [17]
3 years ago
10

Michael's Video charges member $4 to rent each video. If you get a store membership it costs $20 and members only pay $2 to rent

a video. For what number of videos is the cost the same? Write and solve an equation
Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

Thus to rent <u>10</u> number of videos to get the cost same.

Step-by-step explanation:

Given:

Michael's Video charges member $4 to rent each video. If you get a store membership it costs $20 and members only pay $2 to rent a video.

Now, to find the number of videos to get the cost same.

Let the number of videos to get the cost same be x.

Charges to rent each video without membership = $4.

Cost of membership = $20.

Charges to rent each video with membership = $2.

Now, to get the number of videos to get the cost same we write and solve an equation:

4x=2x+20

<em>Subtracting both sides by </em>2x<em> we get:</em>

<em />2x=20<em />

<em>Dividing both sides by 2 we get:</em>

x=10.

Therefore, to rent 10 number of videos to get the cost same.

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Simplify the expression below.
densk [106]
We have:
 (2x ^ 3-12x ^ 2 + 10x-108) / x-6
 Dividing the expression between x-6 we have:
 quotient: 2x ^ 2 + 10
 remainder: - 48
 We can check the result then rewriting the expression:
 2x ^ 3-12x ^ 2 + 10x-108
 = (2x ^ 2 + 10) * (x-6) - 48
 = (2x ^ 3 + 10x - 12 x ^ 2 - 60) - 48
 = 2x ^ 3-12x ^ 2 + 10x-108
 Division OK.
 Answer:
 The result of the division is:
 quotient: 2x ^ 2 + 10
 remainder: - 48


4 0
3 years ago
Find the slope of the line through<br> 1) (15,3), (2,7)
Anuta_ua [19.1K]

Answer:

4/-13

Step-by-step explanation:

The formula for slope is y2-y1 over x2-x1.

5 0
3 years ago
Steve leaves the corner of First and Maple on his bicycle and travels an average speed of 9 mi/hr. Two hours later,his brother l
just olya [345]

Answer:

Two hours later his brother leaves from first and maple and comes after him on a moped travelling 27 mph, His uphill speed was 8 miles per hour slower than his downhill speed.

Step-by-step explanation:

3 0
3 years ago
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
Tlachihualtepetl is a pyramid in Mexico. Each side of the base measures 450 meters and had an original height of 66 meters. How
LenKa [72]

Answer:

44,55,000 cubic meters of treasure could fit the pyramid.

Step-by-step explanation:

We are given the following in the question:

Base measure = 450 meters

Height  = 66 meters

The volume of the pyramid is given by:

V = \dfrac{AH}{3}

where A is the ares of the base and H is the height of the pyramid.

Putting values, we get,

V = \dfrac{1}{3}\times (450\times 450) \times 66\\\\V = 4455000\text{ cubic meters}

Thus, 4455000 cubic meters of treasure could fit the pyramid.

8 0
3 years ago
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