Solve each equation x-6=8

A data set contains information on the grams of fat and number of calories in 28 different fast foods. The correlation coefficie

k0ka [10]

Using a calculator, it is found that for the two-tailed test of significance, the p-value is of 0.9195.

The correlation coefficient is also called <u>Pearson's r-score</u>, and is used for two-tailed tests. To find the p-value, the information needed is:

The value of the Pearson's r-score, that is, the value of the correlation coefficients.
The sample size.

In this problem, we have that the correlation coefficient is of r = 0.02, with a sample size of n = 28.

Using it as the input for a r-score calculator, the p-value is of 0.9195.

A similar problem is given at brainly.com/question/13873630

6 0

2 years ago

During which time period does Landon's elevation change the fastest? Explain how you know?

bogdanovich [222]

<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points $(4,3) \ and \ (8,6)$ why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min$

<em>So London's elevation changes 0.75 inches per minute</em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, $(16,5) \ and \ (18,3)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min$

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

7 0

3 years ago

Find the value of tanθ, if cosθ = 4/5 ; 0° ≤ θ< 90°

Montano1993 [528]

Answer:

3/4

Step-by-step explanation:

<u>Given </u>

cosθ = 4/5
0° ≤ θ < 90°

<u>In the first quadrant both sine and cosine are positive, so as tangent.</u>

tanθ = sinθ / cosθ =
$\sqrt{1 - cos^2}$ θ / cosθ =
$\sqrt{1 - (4/5)^2}$ / 4/5 =
$\sqrt{9/25}$ / 4/5 =
3/5*5/4 =
3/4

4 0

2 years ago

How do you find the domain of a linear grap

IceJOKER [234]

The domain is all possible x values. For linear graphs, the domain is usually all real numbers.

4 0

2 years ago

Read 2 more answers

What is 47+50- __ - 32

Klio2033 [76]

This question doesn't make sense.Are you sure you wrote it correctly?

8 0

2 years ago