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irina1246 [14]
3 years ago
13

The table shows how many miles Brandon has traveled after the specified period of time. Find Brandon's rate in miles per minute

between 15mins=12miles and 20mins=17miles minutes.
A) 1 mile per minute
B) 5 miles per minute
C) 12 miles per minute
D) 17 miles per minute
PLEASE HELP I NEED IT ASAP I WILL MARK BRAINLIEST FOR FIRST PERSON!!
Mathematics
2 answers:
beks73 [17]3 years ago
7 0

Answer:

The answer is one! I just took the test!!

Svetach [21]3 years ago
6 0
None because if you take 15 mins and 1 mile per min then it would equal 15 miles.
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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
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Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

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Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

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