11-3 = 8
8y = 24
8y/8 = 24/8
y = 3
This is so blurry, can you take another picture or type the questions out please/
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
<span>sin(36)(9) = 5.29
cos(36)(9) = 7.28
Area = (1/2)bh
Area = (1/2)(5.29)(7.28)
Area = 19 sq. in.</span>
Answer:
6(x+4)=30
6x+24=30
6x+24-24=30-24
x=6/6
x=1
Step-by-step explanation:
Hope this helps you
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