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pav-90 [236]
3 years ago
6

Analyze the following code:public class Test {public static void main(String[] args) {int[] x = new int[5];int i;for (i = 0; i &

lt; x.length; i++)x[i] = i;System.out.println(x[i]);}}A. The program displays 0 1 2 3 4.B. The program displays 4.C. The program has a runtime error because the last statement in the main method causes ArrayIndexOutOfBoundsException.D. The program has a compile error because i is not defined in the last statement in the main method.
Computers and Technology
1 answer:
lora16 [44]3 years ago
5 0

Answer:

The answer to this question is the option "C".

Explanation:

In the given java program, it will be given an error message that is "ArrayIndexOutOfBoundsException" which means that We're trying to access the illegal index array element. This exception is displayed when the index is either negative or larger than or equal to the array size. and other options are not correct that can be given as:

  • The option A and B will not correct because it will give an error message.
  • The option D is not correct because variable i is defined in the main method.

That's why the answer to this question is the option "C".

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c++ Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value is c
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<u>Answer:</u>

<em>int fNumber,scndNumber = -1,  </em>

<em>dup = 0; </em>

<em>do { </em>

<em>cin >> fNumber; </em>

<em>if ( scndNumber == -1) { </em>

<em>scndNumber = fNumber; </em>

<em>} </em>

<em>else { </em>

<em>if ( scndNumber == fNumber ) </em>

<em>duplicates++; </em>

<em>else </em>

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<em>} </em>

<em>} while(fNumber > 0 );  </em>

<em>cout << dup; </em>

<u>Explanation:</u>

Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>

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