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LuckyWell [14K]
3 years ago
14

CHALLENGE ACTIVITY 4.2.2: Basic while loop with user input. Write an expression that executes the loop while the user enters a n

umber greater than or equal to 0. Note: These activities may test code with different test values. This activity will perform three tests, with user input of 9, 5, 2, -1, then with user input of 0, -17, then with user input of -1. See "How to Use zyBooks" . Also note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.
Computers and Technology
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer:

#include<iostream>

using namespace std;

int main()

{

int userNum;

userNum=9;

while(userNum>=0)

{

  cout<<"Body"<<endl;

  cin>>userNum;

}

cout<<"Done"<<endl;

return 0;

}

Explanation:

  • Use the userNum >= 0 expression that executes the loop while the user enters a number greater than or equal to 0.
  • Print the userNum inside the while loop.
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Binary is a base-2 number system instead of the decimal (base-10) system we are familiar with. Write a recursive function PrintI
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Answer:

In C++:

int PrintInBinary(int num){

if (num == 0)  

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else

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}

Explanation:

This defines the PrintInBinary function

int PrintInBinary(int num){

This returns 0 is num is 0 or num has been reduced to 0

<em> if (num == 0)  </em>

<em>  return 0;  </em>

If otherwise, see below for further explanation

<em> else </em>

<em>  return (num % 2 + 10 * PrintInBinary(num / 2)); </em>

}

----------------------------------------------------------------------------------------

num % 2 + 10 * PrintInBinary(num / 2)

The above can be split into:

num % 2 and + 10 * PrintInBinary(num / 2)

Assume num is 35.

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10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)

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Read 2 more answers
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