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3 years ago

13

christine wants to pour 70.97 grams of salt into a container. so far, she has poured 19.2 grams. how much more salt should chris

tine pour?

1 answer:

nikklg [1K]3 years ago

8 0

70.97 - 19.2 = 51.77 grams <===

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125 thousandths = 1 tenth and ______ thousandths..... HELP

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125 thousandths is the same as .125
Since decimals go tenths, hundredths, thousandths......
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3 years ago

Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1

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Separating variables, we have

$\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx$

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$\displaystyle \int y\,dy = \int x\,dx$

$\dfrac12 y^2 = \dfrac12 x^2 + C$

Given that $y(0)=-1$ , we find

$\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12$

Then the particular solution is

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$y^2 = x^2 + 1$

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and because $y(0)=-1$ , we take the negative solution to accommodate this initial value.

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2 years ago

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4 years ago

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3 years ago

A winery has a vat with two pipes leading to it. The inlet pipe can fill the vat in 5 hours, while the outlet pipe can empty it

Rashid [163]

Answer:

$time=40/3hours\approx 13.3hours$

Step-by-step explanation:

The rates are additive: you can calculate the<em> inlet </em>rate and the <em>outlet</em> rate and add them algebraically, i.e. the inlet rate will be positive and the outlet rate will be negative.

<u>1. Inlet rate:</u>

$1vat/5hours$

<u />

<u>2. Outlet rate:</u>

$1vat/8hours$

<u>3. Net rate:</u>

$\text{Inlet rate - outlet rate}=1vat/5hours-1vat/8hours\\\\ \text{Net rate}=(8-5)vat/40hour=3vat/40hour=(3/40)vat/hour$

<u>4. Time to fill the vat</u>

$rate=amount/time\implies time=amount/rate\\ \\ time=1vat/(3vat/40hour)$

$time=40/3hours\approx 13.3hours$

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3 years ago