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Lynna [10]
4 years ago
15

Solve the system of equations.

Mathematics
1 answer:
Elanso [62]4 years ago
8 0

Answer:

D

Step-by-step explanation:


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A Poker hand consisting of five cards is dealt from a deck of fifty two cards. What is the probability that the Poker hand consi
Ne4ueva [31]

Answer: 108336

Step-by-step explanation:

given data:

cards on deck = 52

Since  2 queens are supposed to be in the  5 card hand. Therefore, 2 queens are choosen since we have a total of  4.

Since  2 Queens have been chosen already choosen. we are left with 3cards out of the hand of 5. This cards are to be choosen from the 48 remaining cards. Similarly same process would be used for other combination of playing cards.

(42∗483)+(43∗482)+(44∗481).

= (6 * 17296) + (4 * 1128 ) + (1 * 48)

= 103776 + 4512 + 48

=108336

3 0
4 years ago
here you go have some points. what is 1+1 see some easy points right here i hope i made your day a little better =)
BARSIC [14]
Its 2 bababoi boi boi
3 0
3 years ago
Read 2 more answers
Describe the transformation.
viva [34]

Answer:

Reflection

Step-by-step explanation:

It is reflecting across the Y axis. It is not a dialation, since it is the same shape, but not a different size. Its not rotation, because it wasnt rotated to get to the new shape. And it is not translation, because it is not exactly the same shape (the shape was mirrored)

7 0
3 years ago
Suppose a quadratic equation has the form x^2 + x + c = 0. Show that the constant c must be less than 1/4 in order for the equat
Mumz [18]

Answer:

see explanation

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

Then for the equation to have 2 real roots , the discriminant must be greater than zero , that is

b² - 4ac > 0

x² + x + c = 0 ← is in standard form

with a = 1, b = 1, c = c , then

b² - 4ac > 0

1² - (4 × 1 × c) > 0

1 - 4c > 0 ( subtract 1 from both sides )

- 4c > - 1

Divide both sides by - 4, reversing the inequality as a result of dividing by a negative quantity.

c < \frac{1}{4}

7 0
2 years ago
Given that a function, g, has a domain of -20 &lt; x &lt; 5 and a range of -5 = g(x) &lt; 45 and that g(0) = -2 and g(-9) = 6, s
scoray [572]

Answer:

A. g(-13)=20

Step-by-step explanation:

For this question we should apply the discard method.

B. g(-4)=-11 can't be true because the range of g is [-5,45); it means that the function won't never take values minor than -5 or higher or equal to 45.

C. g(0)=2. This contradict what is said on the problem: g(0)=-2.

D. g(7)= - 1  This can't be true because the domain of g(x) is (-20,5), which means that the function is not defined in values minor (or equal to) than -20 or higher (or equal to) 5. So, g(7) does not exist.

4 0
4 years ago
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