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Ksenya-84 [330]
3 years ago
6

"How are we ever going to build this bridge?" asks Omkar looking out across the raging river.

Mathematics
1 answer:
Alik [6]3 years ago
3 0

Answer:

The distance across the river from Omkar to the big rock is 72 meters.

Step-by-step explanation:

Using the given information draw as triangle as shown below.

According to angle sum property, the sum of interior angles of a triangle is 180°.

In triangle ABC,

\angle A+\angle B+\angle C=180^{\circ}

98^{\circ}+33^{\circ}+\angle C=180^{\circ}

131^{\circ}+\angle C=180^{\circ}

\angle C=180^{\circ}-131^{\circ}=49^{\circ}

The measure of angle C is 49°.

Sine formula:

\frac{a}{\sin a}=\frac{b}{\sin b}=\frac{c}{\sin c}

Using sine formula in triangle ABC, we get

\frac{AC}{\sin B}=\frac{AB}{\sin C}

\frac{AC}{\sin 33^{\circ}}=\frac{100}{\sin 49^{\circ}}

AC=\frac{100}{\sin 49^{\circ}}\times \sin 33^{\circ}

AC=\frac{100}{0.7547}\cdot0.544639

AC=72.166

AC\approx 72

Therefore the distance across the river from Omkar to the big rock is 72 meters.

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There are no common factors except 1
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Which points are exactly 10 units from the point (–8, –2)? Check ALL that apply.
Archy [21]

Answer:

The points that are exactly 10 units from the point (–8, –2) are (2, –2)  and (–8, 8).

Step-by-step explanation:

The distance formula is;

                               d= \sqrt{( x_{2}-x_{1} )^{2}-(y_{2} -y_{1} )^{2}   }

So for distance between: (–8, –2)  and (2, –2) is:

                             d=  \sqrt{( 2-(-8))^{2}-(-2 -(-2) )^{2}   }

                             d= \sqrt{100}

                            d= 10 unit

Similarly for distance between: (–8, –2) and (–8, 8) is,

                                d=  \sqrt{( -8-(-8))^{2}-(8 -(-2) )^{2}   }

                               d= \sqrt{100}

                               d= 10 unit

6 0
3 years ago
Questions in Image below. Please explain how you got your answers in depth please.
irakobra [83]

Step 1

Revenue (sometimes referred to as sales revenue) is the amount of gross income produced through sales of products or services. This, in the context of the question, means that the revenue generated from the sales of tickets is given by the function below. We are now required to find the price that tickets will be sold at in a day based on the function that will make the revenue to be equal to $0.

The revenue is given by the function;

\begin{gathered} f(p)=150p-5p^2 \\ f(p)\text{ is the revenue and should be equal to 0 according to the question.} \\ p=\text{ The price of tickets for the day for the revenue to be 0} \end{gathered}

To solve this problem or to find this price at which tickets will be solved to give us zero revenue, we must equate the given function for the revenue to 0 and find the value of p, the price of the tickets that make the function to be equal to 0.

For the theatre to make $0 in revenue, this means f(p)=0.

Therefore, we will equate f(p) to 0

Step 2

Equate f(p) to 0

\begin{gathered} 0=150p-5p^2 \\ p(150-5p)=0----(\text{factorize)} \\ p=0 \\ 0r \\ 150-5p=0 \\ 150=5p \\ \frac{5p}{5}=\frac{150}{5} \\ p=30 \\ p=0\text{ or 30} \end{gathered}

Therefore the revenue to be zero, the price of the ticket will be $0 or $30 but the question asked us how high the ticket price will be to get a revenue of 0. Both 0 and 30 gave us revenue of 0 but $30 is higher therefore, the answer will be $30.

Check;

\begin{gathered} 150p-p^2=0 \\ \text{If the price of tickets=0} \\ 150(0)-5(0^2)=0 \\ \text{If p=30} \\ 150(30)-5(30^2)=4500-4500=0 \end{gathered}

Both give us 0 revenue but $30 is higher and the right answer.

Step 3

The equation you can write for revenue of $700 is;

\begin{gathered} 700=150p-5p^2 \\ 5p^2-150p+700=0_{} \end{gathered}

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Answer:

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Step-by-step explanation:

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