Rectangle diagonals are equal.
2(5a+1) = 2(a+1)
10a + 2 = 2a + 2
10a -2a = 2 - 2
8a = 0
⇒ a = 0
AC = 2(5a+1) = 2(5 × 0 +1)= 2(0 + 1) = 2 × 1 = 2 <span>
</span>BD = 2(a+1) = 2(0 + 1) = 2 <span>× 1 = 2
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Ansver: AC = BD = 2
f(x) - g(x)
=> (3x² + x - 3) - (x² - 5x + 1)
=> 3x² + x - 3 - x² + 5x - 1
=> 3x² - x² + x + 5x - 3 - 1
=> 2x² + 6x - 4
Let's find the base first.
9*24*1/2 = 9*12 = 108
Now we multiply that by 2, as there are 2 triangles.
108*2 = 216
We'll find the 15 by 20 side next.
15 * 20 = 300.
Multiply that by 2, as there are 2 rectangles of those dimensions.
300*2 = 600
The last side is the 24 by 20 side.
24*20 is 480.
There's only one of those rectangles, so we won't multiply it by 2.
Now, we'll add all of our areas together.
216+600+480 = 1296.
Therefore the answer is A, 1296 in^2.
Hope that helps! :)
Answer: True
The domain and range swap when you go from the original function to the inverse. This is because the x and y swap places. Recall that the domain is the set of possible x inputs and the range is the set of possible y outputs.
5+5=10, 5+6=11, 5+7=12,etc.