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Brrunno [24]
1 year ago
8

Identify a3 of this sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5, … a3 =

Mathematics
1 answer:
Advocard [28]1 year ago
3 0
The answer should be .75
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I need help with this please
djyliett [7]

Answer:

Step-by-step explanation:

The last three are irrational but I'm not sure about the first four.

3 0
3 years ago
a(x+b)=4x+10 in the equation above a and b are constants. if the equation has infinitely many solutions for X, what is the value
xeze [42]

Answer:

b= \frac{5}{2}

Step-by-step explanation:

Given

a(x+b)=4x+10\\ax+b= 4x+10\\

Now we know that system has infinite solution for x

\frac{a_1}{a_2}=\frac{b_1}{b_2}

in above equation.

a_1=a, a_2=4, b_1=ab,b_2=10\\

∴\frac{a}{4}=\frac{ab}{10}\\\therefore b=\frac{10\times a}{4\times a}=\frac{5}{2}

7 0
3 years ago
AB = 3 + x
ICE Princess25 [194]

The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.

<u>Step-by-step explanation</u>:

ABCD is a quadrilateral with their opposite sides are congruent (equal).

The both pairs of opposite sides are given as AB = 3 + x , DC = 4x , AD = y + 1 , BC = 2y.

  • AB and DC are opposite sides and have same measure of length.
  • AD and BC are opposite sides and have same measure of length.

<u>To find the length of AB and DC :</u>

AB = DC

3 + x = 4x

Keep x terms on one side and constant on other side.

3 = 4x - x

3 = 3x

x = 1

Substiute x=1 in AB and DC,

AB = 3+1 = 4

DC = 4(1) = 4

<u>To find the length of AD and BC :</u>

AD = BC

y + 1 = 2y

Keep y terms on one side and constant on other side.

2y-y = 1

y = 1

Substiute y=1 in AD and BC,

AD = 1+1 = 2

BC = 2(1) = 2

Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.

6 0
3 years ago
Monica measures 91 milliliters of water into 9 tiny beakers. she measures an equal amount of water into the first 8 beakers. she
UkoKoshka [18]
To determine the amount of water in the first 8 beakers, you will subtract the 19 ml that are in the 9th beaker from the total to see how much water was actually put into the first 8 beakers.

91 ml - 19 ml = 72 ml.

The 72 ml are divided evenly between 8 beakers.

72/8 = 9 ml

There would be 9 ml of water in each of the first 8 beakers.
8 0
3 years ago
A=v1-v0/t solve for v1
Tom [10]
A=v1-v0/t
a*t=v1-v0
(a*t)+v0=v1
3 0
3 years ago
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