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Brrunno [24]
2 years ago
8

Identify a3 of this sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5, … a3 =

Mathematics
1 answer:
Advocard [28]2 years ago
3 0
The answer should be .75
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A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
Help??? Which Choice is correct
marusya05 [52]

Answer:

choice B should be right

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Polygons consist of line segments connected only at their endpoints. Many types of polygons exist, with varying side and angle m
aleksley [76]

Answer:

its asking for your opinion

8 0
3 years ago
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = \frac{3}{4},

q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28

       = 6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28

       = (\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28

       = (\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}

       = -\frac{1666}{64}

       = -\frac{833}{32} ≠ 0

Therefore, Yuri is not correct. x = \frac{3}{4} can not be a root of the given expression.

6 0
3 years ago
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A cone is inscribed in a right square pyramid. What is the remaining volume if the
diamong [38]

Answer:

3tgfjhihvyuvyuhihhibib

4 0
3 years ago
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