1. 4(1, 4)
2. 5(4, 13)
3. 2(x, 2)
4. 14x(y, 3)
Answer:
I think its two eqautions
MN and QR are corresponding :-)
I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.
Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:
a = 1
b = 2
c = 3
d = 4


Simplify into standard form:



Use the quadratic formula to solve:

For functions in the form of

. So in this case:
a = 1
b = -4
c = 2
Plug them in:

Solve for 'x':




So the answer would be A.
Answer:
Have you gotten the answer. if yes Hmu... Aihs I sit beside you
Step-by-step explanation: