Ask question

Ask question

All categories

3 years ago

8

Who can tutor me for free

1 answer:

krok68 [10]3 years ago

4 0

Answer:

Do not ask for free tutoring (Nobody will really do it)

Step-by-step explanation:

Just use Brainly! Ask for questions and explanations and do what you can to get your work done. After that if you need further help then ask a parent/guardian/sibling or someone you know for help and if that doesn't work then come back to this. Hope this helps.

You might be interested in

Find the geometric mean of 275 and 11 275/x=x/11 x^2= 3025 x=sq rt 3025 now I'm not sure what to do.

Bogdan [553]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
you got it
<span>except keep going to get </span>
<span>x = ±√3025 </span>
<span>x = ± 55 </span>

<span>check: </span>
<span>275 , 55, 11 </span>
<span>is 55/275 = 11/55 ? YES </span>
<span>is -55/275 = 11/=55 ? YES</span>

6 0

3 years ago

Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...

katovenus [111]

Answer:

$a_{12}=-244140625$

Step-by-step explanation:

Considering the geometric sequence

$5,-25,\:125,\:...$

$a_1=5$

As the common ratio ' $r$ ' between consecutive terms is constant.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$r=\frac{-25}{5}=-5$

$r=\frac{125}{-25}=-5$

The general term of a geometric sequence is given by the formula:

$a_n=a_1\cdot \:r^{n-1}$

where $a_1$ is the initial term and $r$ the common ratio.

Putting $n = 12$ , $r = -5$ and $a_1=5$ in the general term of a geometric sequence to determine the 12th term of the sequence.

$a_n=a_1\cdot \:r^{n-1}$

$a_n=5\left(-5\right)^{n-1}$

$a_{12}=5\left(-5\right)^{12-1}$

$=5\left(-5^{11}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-5\cdot \:5^{11}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=-5^{1+11}$ ∵ $5\cdot \:5^{11}=\:5^{1+11}$

$=-244140625$

Therefore,

$a_{12}=-244140625$

6 0

3 years ago

Solve the equation x³ − 5 = 59

In-s [12.5K]

Answer:

4 = x

Step-by-step explanation:

x³ - 5 = 59 Add five to both sides of the equation.

x³ = 64 Now find the cubed root of 64

∛64 = 4

x = 4

3 0

3 years ago

Prove this trigonometric identity<br>sin 3x/sin x - cos 3x/cos x =2

Sveta_85 [38]

Step-by-step explanation:

LHS= sin 3x/sin x - cos 3x/cosx

Taking LCM,

<u>=</u><u>sin3xcosx- cos3xsinx</u>

sinxcosx

<u>=</u><u>sin(3x-x)</u>

sinxcosx

= <u>2sin2x</u>

2sinxcosx

=<u> </u><u>2sin2x</u><u> </u>

sin2x

=2

= RHS.

Proved.

8 0

4 years ago

What is the area of the following shape

Valentin [98]

Answer:

i think you multiply them i could be mistaken

4 0

3 years ago

Read 2 more answers