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mezya [45]
3 years ago
10

27.) If a ≠ 0, then lim (x^2 - a^2)/(x^4 - a^4) is: x->-a

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

\frac{1}{2a^2}

Step-by-step explanation:

Step 1: Write limit

\lim_{x \to -a} \frac{x^2-a^2}{x^4-a^4}

Step 2: Factor

\lim_{x \to -a} \frac{(x+a)(x-a)}{(x+a)(x-a)(x^2+a^2)}

Step 3: Simplify

\lim_{x \to -a} \frac{1}{x^2+a^2}

Step 4: Substitute

\frac{1}{(-a)^2+a^2}

Step 5: Evaluate

\frac{1}{a^2+a^2}

Step 6: Simplify

\frac{1}{2a^2}

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3 years ago
Pre cal/cal master needed
weqwewe [10]
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2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
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Combine:  2x^2      =  2x^2 
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So all we have left is
2x^2 - 5x





5 0
3 years ago
In variogram modeling with multiple variables and anisotropy, if all the variograms cannot be modeled well, it is critical to mo
siniylev [52]

Answer:

The statement is false.

Step-by-step explanation:

If the modeling is with multiple variables it is necessary for all the variables to be modeled well such that the criticality of the model is dependent on all the variograms. It is not dependent on the cross variograms only.

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Hello,
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Bye :-)
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Solve the system of equations. Show ALL your work. Put your answer in the form of an ordered pair (x, y)
stiv31 [10]
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation. 
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The ordered pair is therefore (10,5).
6 0
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